ANALYTICAL GEOMETRY.

1. The branch of science which has obtained the name of analytical geometry owes its origin to Descartes. It consists in the application of algebra to geometry, not merely by using algebraic symbols as the representatives of magnitude, but by employing these in such a manner that the position of a point is indicated by referring it to fixed lines or planes, just as the position of a point on the earth's surface is defined by referring it to the equator and the first meridian. For example, if we suppose the positions of two lines at right angles to one another to be fixed and known, then the position of any point in the same plane is sufficiently determined by its distances from these two lines, just as the

position of a place on a given map is denoted by its latitude and longitude.

This science, like that of ordinary geometry, is divided into two parts, plane and solid, or analytical geometry of two and of three dimensions.

ANALYTICAL GEOMETRY OF TWO DIMENSIONS.

2. As every line or area is supposed to be situated in one plane, we may, whenever it is convenient to do so, imagine that plane to be the paper before us, which, for convenience of phraseology, we may further suppose to be standing

upright, so that any one line of print is horizontal, whilst the successive lines lie vertically under each other. The simplest way, under these circumstances, in which the position of a point can be indicated, will be by its distances from two lines at right angles to each other, the one horizontal, the other vertical. If we know the positions of these lines, then we know the position of every point in this plane whose distances from these two lines have been given us. But it is frequently necessary to adopt lines of reference inclined to one another. In this case, the position of a point is determined by its two distances from these lines respectively, each measured in a direction parallel to the other. The lines of reference are called the co-ordinate axes; their point of intersection is called the origin; the distances of any other point from the lines, measured in the way stated above are called the co-ordinates of that point; of these one is called the abscissa, the other the ordinate, the former being usually the designation of the horizontal distance.

Figure 1: A diagram showing a point P in a coordinate system with axes OX and OY. A line y passes through the origin O. A horizontal line segment PM is drawn from P to the x-axis at M. A vertical line segment PN is drawn from P to the line y at N. The distance OM is the abscissa, and PN is the ordinate.
Fig. 1.

In this figure, OX, OY, at right angles or not, are called the co-ordinate axes; O the origin; PM, PN (or its equal OM), drawn parallel to OY and OX, the co-ordinates of the point P; OM the abscissa, PM the ordinate. The line OM is usually written by the letter x, and MP by y. We may thus form some idea of the meaning of the symbols by considering the letter x as the abbreviation for the general word longitude, and the letter y as that for latitude. Thus when the latitude and longitude are both specified, the point referred to is determined. If, on the other hand, there is stated merely a relation between them, such, for example, as that the latitude is equal to the longitude, it is clear that no one point is determined thereby, since the same property is applicable to an innumerable series of points. A little consideration will show that some line, straight or crooked, will pass through all such points. The relation, therefore, is said to determine this line, and when expressed in algebraic symbols, is called the equation to the line. Thus, for example, the relation, "that the abscissa is equal to the ordinate," or the longitude equal to the latitude, understood as above, indicates a straight line; and the corresponding equation, x=y, is the equation to a straight line.

3. The requirements of analysis demand that attention should be paid to the sign as well as to the magnitude of the algebraic symbol which expresses an abscissa or an ordinate. We lay it down as a rule, deduced at once from the algebraic definitions of the symbols + and -, that if one of them denotes a line measured in one direction, the other will denote a line measured in the opposite direction. Thus if x = +a be an abscissa measured to the right of O, x = -a will be an equal abscissa measured to the left; if y = +b be an ordinate measured above O, y = -b will be an equal ordinate measured below it; and these are the directions which we shall usually assign to the positive and negative abscissas and ordinates.

4. Besides the method of representation which we have described, there is another very unlike it in form, but equally important in the solution of mechanical and astronomical problems. In this system, the position of a point is determined by its distance from a given point, and the direction in which the line measuring that distance lies with respect to a given line. This system is called the system of polar co-ordinates. The given point to which all others are referred is called the pole, and the distance from that point the radius vector.

5. The subject before us naturally divides itself into

three distinct branches,—1°, the determination of the equations to curves from the knowledge of their properties; 2°, the determination of the forms and properties of curves from their equations; and, 3°, the deduction of one property of a curve from another, or from several others. The third branch being the combination and extension of the other two, we propose briefly to illustrate the first and second, and then to include under the third a discussion of some of the more important properties of the Conic Sections in the form in which the requirements of science demand their exhibition.

SECTION I.—THE DETERMINATION OF THE EQUATIONS TO CURVES FROM THE KNOWLEDGE OF THEIR PROPERTIES.

6. a. The Straight Line.—The property of the straight line which we shall employ is this—that if two series of parallel lines be drawn from any points in it so as to form with the given line a series of triangles, the sides of these triangles will be proportional.

Let PQR be the straight line; OX, OY the co-ordinate axes; PM parallel to OY, and QE parallel to OX: the triangles PQE, QRO are similar, \therefore PE : EQ :: QO : OR.

Let OM be called x, or OM = x, MP = y, OQ = b; and let the ratio QO : OR be a : 1.

\text{then } y = b : x :: a : 1;
\text{or } y = ax + b \text{ is the equation to the line PR.}

Hence it is clear that any simple equation between y and x will represent a straight line. If the axes of co-ordinates are at right angles to each other—in which case they are called rectangular axesa is the trigonometrical tangent of the angle PRO, in which the given line cuts the axis of x.

7. The equation to a straight line may be written in a different form, which is frequently convenient, thus:

Let the perpendicular from O on the line PR be called p, the angle PRM \alpha; then it is evident that

y \cos \alpha - x \sin \alpha = p = 0,

which is the equation to the line.

This equation is abbreviated by writing for it simply \alpha = 0; or, when multiplied by a constant a, by u = 0; where u is a function of x, y, \alpha, p, and a constant which is arbitrary. We shall give an instance of the use of this form of the equation in the sequel.

If the axes of co-ordinates are not at right angles, the equation becomes slightly changed in form.

Let the line make the angles \theta and \phi with the axes of x and y respectively; then

QO : OR :: \sin \theta : \sin \phi;
\therefore y = \frac{\sin \theta}{\sin \phi} x + b \text{ is the equation;}
\text{or } y \sin \phi - x \sin \theta = b \sin \phi;

consequently all lines which are parallel to the given line, or for which \theta and \phi are the same, have the relative magnitudes of the co-efficients of x and y the same, and vice versa.

8. COR. 1.—If the line pass through a given point of which the co-ordinates are x', y', we shall have y = ax + b generally,

\text{and } y' = ax' + b \text{ for the given point;}
\therefore y - y' = a(x - x'),

or b is determined.

COR. 2.—If the line pass through a second given point whose co-ordinates are x'', y'', we shall have y' - y'' = a(x' - x''), or a is determined,

\text{and } \therefore y - y' = \frac{y'' - y'}{x'' - x'} (x - x') \text{ is the equation.}

9. To express the polar equation to the straight line. Let O be the pole, OY perpendicular to PR; and suppose OP joined. Let OP = r, OY = p, \angle POR = \theta, \angle YOR = \alpha; then OP \cos \angle POY = OY, or r \cos (\theta - \alpha) = p is the equation required.

10. b. The Circle.—The property of the circle is, that the lines drawn from the centre to the circumference are equal.

Let us suppose the axes to be rectangular, Q the centre, QP the radius = a; OM = x, PM = y, the co-ordinates of P; ON = b, NQ = c, the co-ordinates of the centre; then PR^2 + QR^2 = PQ^2; or (y-c)^2 + (x-b)^2 = a^2 is the equation required. If the origin be at the centre, the equation is x^2 + y^2 = a^2.

Figure 3: A circle centered at Q in a Cartesian coordinate system. The x-axis and y-axis are shown. A point P is on the circle, with its coordinates (x, y) indicated. The center Q has coordinates (b, c). The radius QP is labeled 'a'. The distance from the y-axis to the center is 'c', and from the x-axis to the center is 'b'.
Fig. 3.

11. The polar equation in its simplest form, when the centre is the pole, is evidently r = a.

12. c. The Parabola.—The property (CONIC SECTIONS, Part 1, Def. 1) is, that the distance of any point from the focus is equal to its distance from the directrix.

Let F be the focus, DQ the directrix, then FP = PQ. Suppose the vertex A to be the origin, and AFX the axis of the parabola to be the axis of x.

Let AM = x, MP = y, AF = AD = a, then PM^2 + MF^2 = PQ^2 = PQ^2 = MD^2; or y^2 + (x-a)^2 = (x+a)^2, which gives y^2 = 4ax, the equation required.

Figure 4: A parabola opening to the right with vertex A at the origin. The x-axis is the axis of symmetry. A point P is on the parabola with coordinates (x, y). The focus F is at (a, 0). The directrix is a vertical line at x = -a. The distance from the vertex to the focus is 'a'. The distance from the vertex to the directrix is '2a'.
Fig. 4.

13. To find the polar equation, the focus being the pole.

Let FP = r, DFP = \theta; then FP \cos \angle PFM = FM = DM - DF = PQ - DF = FP - DF = r - 2a

\therefore r = \frac{2a}{1 - \cos \angle PFM} = \frac{a}{\sin^2 \frac{1}{2} \angle PFM} = \frac{a}{\cos^2 \frac{1}{2} \theta} \text{ is the equation required.}

14. d. The Ellipse.—The property (CONIC SECTIONS, Part 2, Def. 1) is, that the sum of the two lines drawn from any point to the two foci is constant.

Let the centre C be the origin; CA which passes through the focus S, called the semi-axis major, or the semi-transverse axis, the axis of x; CB perpendicular to CA, the semi-axis minor, or the semi-conjugate axis, the axis of y; CM = x, MP = y, CA = a, CB = b; then it is evident that CF^2 = CS^2 = a^2 - b^2; and the condition FP + SP = 2a gives

\begin{aligned} FP^2 &= (2a - SP)^2 = 4a^2 - 4a \cdot SP + SP^2, \\ \text{or } (FC + x)^2 + y^2 &= 4a^2 - 4a \cdot SP + (CS - x)^2 + y^2; \\ \text{whence } 2FC \cdot x &= 4a^2 - 4a \cdot SP - 2CS \cdot x, \\ \text{or } a \cdot SP &= a^2 - CS \cdot x; \end{aligned}
\begin{aligned} \text{that is, } a^2(SM^2 + MP^2) &= a^2 - 2a^2 \cdot CS \cdot x + CS^2 \cdot x^2, \\ \text{or } a^2(x - CS)^2 + a^2y^2 &= a^2 - 2a^2 \cdot CS \cdot x + CS^2 \cdot x^2; \\ \text{whence } a^2x^2 + a^2y^2 &= a^2 + CS^2 \cdot x^2, \\ \text{or } a^2y^2 + b^2x^2 &= a^2b^2, \text{ the equation required.} \end{aligned}
Figure 5: An ellipse centered at C in a Cartesian coordinate system. The x-axis is the major axis, and the y-axis is the minor axis. The semi-major axis is 'a' and the semi-minor axis is 'b'. The foci S and S' are on the major axis. A point P is on the ellipse with coordinates (x, y). The distance from the center to the focus is 'c'.
Fig. 5.

15. Con.—Since a \cdot SP = a^2 - CS \cdot x, if CS = ae, we shall have SP = a - ex; and since SP + FP = 2a, FP = a + ex. Also it is evident that a^2e^2 = a^2 - b^2, or e^2 = 1 - \frac{b^2}{a^2}. e is called the eccentricity.

16. To find the polar equation to the ellipse, the focus being the pole.

Let SP = r, PSA = \theta, then PSD = \pi - \theta. But (Art. 15) SP = a - ex,

\begin{aligned} \text{where } x &= CM = CS - SM = ae - r \cos \angle PSM; \\ \therefore r &= a - ae^2 + er \cos \angle PSM; \end{aligned}
r = \frac{a(1 - e^2)}{1 - e \cos \angle PSM} = \frac{a(1 - e^2)}{1 + e \cos \theta}

is the equation required.

17. e. The Hyperbola.—The property is (CONIC SECTIONS, Part 3, Def. 1), that the difference of the two lines drawn from any point to the two foci is constant.

The figure being drawn, and the same letters retained as for the ellipse, we shall have FP - SP = 2a, which equation being treated as the corresponding equation for the ellipse, will give, first, a \cdot SP = CS \cdot x - a^2; and, finally (if CS^2 = a^2 + b^2), a^2y^2 - b^2x^2 = -a^2b^2 is the equation required.

18. \text{ The polar equation is } r = \frac{a(e^2 - 1)}{1 + e \cos \theta}

19. f. The Cissoid of Diocles.—This curve is generated by the following construction: AQB is a semi-circle, of which AB is the diameter; AQ is any chord; QN perpendicular to the diameter; PM is drawn parallel to QN at such a distance that AM = BN: the point P, in which the chord AQ and the line

Figure 6: A geometric construction for the cissoid of Diocles. A semi-circle AQB is drawn on diameter AB. A chord AQ is drawn. A perpendicular QN is dropped from Q to the diameter AB. A line segment PM is drawn parallel to QN, with M on AB such that AM = BN. The intersection of AQ and PM is point P. The curve APD is the cissoid.
Fig. 6.

PM intersect one another, is a point in the cissoid APD: the cissoid is said to be the locus of the point P.

\begin{aligned} \text{Let } AB &= 2a, AM = x, MP = y, \\ \text{then } y^2 &: x^2 :: QN^2 : AN^2 :: AN \cdot NB : AN^2 \\ &:: NB : AN :: x : 2a - x; \end{aligned}
\therefore y^2 = \frac{x^3}{2a - x} \text{ is the equation required.}

20. To find the polar equation.

Join BQ; let AP = r, \angle PAM = \theta; then because AQB is a right angle,

\begin{aligned} AQ &= AB \cos \theta, \therefore AN = AB \cos^2 \theta, \\ \text{and } AM &= r \cos \theta, \therefore r \cos \theta = AB - AB \cos^2 \theta = AB \sin^2 \theta, \\ \text{and } r &= \frac{2a \sin^2 \theta}{\cos \theta} \text{ is the equation required.} \end{aligned}

21. g. The Conchoid of Nicomedes.—This curve is generated as follows:—

A line of indefinite length revolves on and also slides in a fixed pivot; whilst a constant portion of the line always projects beyond a given fixed straight line, the extremity of the projecting line traces out a conchoid; or the conchoid is the locus of the extremity.

Let C be the pivot, AB the fixed line; PQ the constant portion of the revolving line which projects above it. Draw CA perpendicular to AB. Let PQ = a, CA = b, AM = x, MP = y.

By similar triangles,—
PL^2 : LC^2 :: PM^2 : MQ^2 :: PM^2 : PQ^2 - PM^2; or (y + b)^2 : x^2 :: y^2 : a^2 - y^2; or x^2y^2 = (y + b)^2 (a^2 - y^2); which is the equation required.

22. To find the polar equation. Let C be the pole,

Figure 7: A geometric construction for the conchoid of Nicomedes. A line segment PQ of length 'a' is fixed. A line segment CA of length 'b' is perpendicular to the line containing PQ. A line segment AM of length 'x' is drawn from A along CA. A line segment MP of length 'y' is drawn from M perpendicular to AM. The curve PL is the conchoid.
Fig. 7.

Analytical Geometry. CP = r, \angle ACP = \theta; then since CQ \cos \theta = CA, we get (r-a) \cos \theta = b, the polar equation.

23. h. The Cycloid.—This curve is described by a point in the circumference of a circle which rolls along a straight line.

Let GPD be the circle which rolls along the straight line BR, the point P in the circumference of the circle will trace out a curve BAR, which is the cycloid.

Let A be the highest point of the curve; GD = 2a the diameter of the generating circle; AM = x, MP = y; O the centre of the circle; \angle POG = \theta; then it is evident that the circumference of the circle coincides by succession with the straight line BR; therefore are PD = BD, arc GPD = BC, and arc GP = DC; hence

x = GL = a \text{ vers } \theta,
y = ML + LP = PG + PL = a\theta + a \sin \theta,

or y = a \text{ vers}^{-1} \frac{x}{a} + \sqrt{2ax - x^2} is the equation required.

24. i. The Lemniscate.—The property of this curve is that the product of the two lines drawn from any point of it to the two foci is always equal to the square of half the distance between the foci.

Let F and S be the foci, FC = CS = a, CM = x, MP = y; the property is that FP \times SP = a^2.

Figure 9: A diagram of a lemniscate curve. It shows a horizontal line with points F, C, M, S, and A. F and S are foci, C is the center, and M is a point on the curve. A vertical line segment MP is drawn from M to the curve. Lines FP and SP are also shown, forming a triangle FSP.
Fig. 9.
\text{Hence } \sqrt{(a+x)^2 + y^2} \times \sqrt{(a-x)^2 + y^2} = a^2;
\text{or } (y^2 + x^2 + a^2 + 2ax)(y^2 + x^2 + a^2 - 2ax) = a^4;
\text{or } (y^2 + x^2 + a^2)^2 - 4a^2x^2 = a^4;
\text{or } (y^2 + x^2)^2 + 2a^2y^2 - 2a^2x^2 = 0;
\text{or } (y^2 + x^2)^2 = 2a^2(x^2 - y^2) \text{ is the equation required.}

25. To find the polar equation. Let CP = r, \angle PCS = \theta; then

FP^2 = r^2 + a^2 + 2ar \cos \theta;
SP^2 = r^2 + a^2 - 2ar \cos \theta;
FP^2 \times SP^2, \text{ or } a^4 = (r^2 + a^2)^2 - 4a^2r^2 \cos^2 \theta;

whence r^2 = 4a^2 \cos^2 \theta - 2a^2
= 2a^2(2 \cos^2 \theta - 1)
= 2a^2 \cos 2\theta is the equation required.

26. Besides the cycloid there are other curves which are generated by a point in a rolling circle. The trochoid differs from the cycloid in having the generating point within the circle at a distance b from the centre. Its equations are

x = a - b \cos \theta
y = a\theta + b \sin \theta.

The epicycloid is traced out by a point in the circumference of a circle which rolls on the convex circumference of another circle.

The hypocycloid is traced out by a point in the circumference of a circle which rolls on the concave circumference of a larger circle.

If the describing point is not in the circumference of the rolling circle, the curves become the epitrochoid and hypotrochoid respectively.

SECTION II.—THE DETERMINATION OF THE FORMS AND PROPERTIES OF CURVES FROM THEIR EQUATIONS.

27. Since very few curves can be described by a continuous motion, it is evident that, with rare exceptions, the determination of the form of a curve must resolve itself either into the expression of the numerical values of all coordinates corresponding to given abscissas, or into a general investigation of the number and nature of the branches of the curve, their flexure and mutual intersections. It is under the latter aspect that we are about to regard this subject.

With respect to those few curves which can be described by a continuous motion, the modes of description of some of the most important have been already given in the treatise on CONIC SECTIONS, whilst others, such as the cycloid, involve a mechanical process so obvious that it is quite superfluous to waste words in attempting to make it plain. We proceed then at once to describe the general features of a few curves from their equations. This description we shall designate as TRACING THE CURVE.

28. a. The cubical parabola of which the equation is a^2y = x^3.

When x=0, y=0, which shows that the curve passes through the origin. When x is positive, y is positive, which shows that to the right the curve lies above the axis of x. When x is negative, y is negative, which shows that to the left the curve lies below the axis of x.

Since a^2 \frac{dy}{dx} = 3x^2, it follows that

at the origin the axis of x is a tangent to the curve (FLUXIONS, Art. 65, Equation 3). The form of the curve is therefore as in the figure.

29. b. The semi-cubical parabola, of which the equation is ay^2 = x^3.

When x=0, y=0. When x is positive y^2 is positive, or y has two equal values, one + the other -; which shows that there are two similar branches of the curve to the right of the origin, the one above and the other below the axis of x. When x is negative y^2 is negative, and y is impossible; or there is no portion of the curve to the left of the axis of x. The figure is like the outline of the head of a spear, or is a cusp.

30. c. The curve whose equation is y = \frac{x^3}{x^2+1}. It is evident that its general form will be something like that of the cubical parabola already traced. But the equation may be thrown under the form y = x - \frac{1}{x} + c, which shows that

as x increases the value of y tends continually to be equal to it; which is equivalent to the fact that the curve constantly approaches a straight line whose equation is y = x. This straight line is called an asymptote to the curve. An example of a similar line has already been given in the article CONIC SECTIONS (iii. 15) in the case of the hyperbola. A more instructive example will be seen in the conchoid already described, where, from the nature of the case, it is at once evident that the curve continually approaches the straight line AB, without ever reaching it.

To ascertain whether a curve has an asymptote or not, it is sufficient to expand its equation in a descending series of powers of x.

If the portion which remains, after excluding that which becomes 0 on x becoming infinite, be in the form of a simple equation, that equation represents the asymptote. In addition to this there may be an asymptote parallel to the axis of y, which can be ascertained by y becoming infinite for some finite value of x.

31. d. There is another circumstance to be noted respecting the curve we have been discussing. Near the origin where the axis of x is a tangent, it is evidently convex to that axis; but from the nature of the case it is clear that at a considerable distance from the origin it must be convex towards its asymptote, and consequently concave towards the axis of x. The point at which it changes from convex to concave is called a point of inflexion or a point of contrary flexure. To ascertain the position of this point, it is necessary to find the value of x which shall render \frac{d^2y}{dx^2} = 0.

Analytical Geometry. On solving this equation we shall obtain x = \pm \sqrt{3}, which gives the point of inflexion. The curve is therefore as follows (fig. 11), OB being the asymptote, and P the point of inflexion.

Figure 11: A graph of a cubic curve in a Cartesian coordinate system. The curve passes through the origin (0,0) and has an asymptote along the positive x-axis labeled OB. A point P is marked on the curve in the first quadrant, representing the point of inflexion. The curve is symmetric about the origin.
Fig. 11.

32. e. To trace the curve of which the equation is

xy^2 = (x-a)(x-b)(x-c).

Suppose a the least, and c the greatest of the three magnitudes. We have

y = \sqrt{\frac{(x-a)(x-b)(x-c)}{x}};

from which it is clear that in all cases there are two values of y equal and with opposite signs; or, in other words, there is symmetry with respect to the axis of x.

When x=0, y is infinite, or the axis of y is an asymptote.

When x < a, y is impossible, or no branch of the curve lies between the origin and the distance a to the right.

When x=a, y=0; when x > a < b, y is possible; and when x=b, y=0; the curve accordingly starts from the axis of x at the distance a from the origin, and returns to it again at the distance b. This branch of the curve is consequently a kind of oval. If it be required to ascertain where is the broadest part of the oval, it will be necessary to find at what point y is a maximum by the method given in FLUXIONS, art. 60. The result is obtained by the solution of a cubic equation.

When x > b < c, y is impossible.

When x=c, y=0; when x > c, y is possible; and when x is infinite, y is infinite—the branch beyond the distance c consequently starts from the axis of x, and extends to infinity, somewhat in the form of a parabola. When x is negative, y is always possible; and it is infinite both when x is 0 and when x is infinite—diminishing from the first point and then increasing to the second. At some point it must attain a minimum value, which can be ascertained as the maximum above. The branch to the left of the origin accordingly bears some faint resemblance to an hyperbola. The whole curve is as in the figure where O is the origin—OA=a, OB=b, OC=c.

Figure 12: A graph of the curve from problem 32e. It shows three branches on a Cartesian plane. One branch is an oval-like shape between x=a and x=b. Another branch starts at x=c and extends to positive infinity. A third branch is on the negative x-axis, extending to negative infinity. The origin is labeled O, and points A, B, and C are marked on the positive x-axis.
Fig. 12.

33. f. In the last example we assumed that a, b, and c are all different from each other. If we suppose a=b, we have

the equation y = (x-a) \sqrt{\frac{x-c}{x}}. The peculiarity in this equation is this—that when x=a, y=0, which gives a possible point A; but when x is a little greater or less than a, y is impossible, so that no branch of the curve lies near the point. This point, an isolated point where co-ordinates satisfy the equation, but which does not belong to any branch of the curve, is called a conjugate point. By comparing this example with the last, of which it is a particular case, we shall be able to trace the origin of such a point in the oval AB, which has collapsed.

We will now give an example or two of the use of polar co-ordinates.

34. g. The Lemniscate, of which the equation (i) is r^2 = 2a^2 \cos 2\theta.

When \theta=0, r^2=2a^2, r=\pm a\sqrt{2}; or r has two equal values, CA and CB in the figure of Art. 24.

Analytical Geometry. When \theta < \frac{\pi}{4}, r is possible, having two equal values, positive and negative, the former giving the upper half of the right-hand portion, and the latter the lower half of the left.

When \theta = \frac{\pi}{4}, r=0; when \theta > \frac{\pi}{4} < \frac{3\pi}{4}, r is impossible.

When \theta = \frac{3\pi}{4}, r=0; when \theta = \pi, r=\pm a\sqrt{2}, thus giving the upper portion of the left-hand figure, and the lower portion of the right.

35. h. The Cardioide, of which the equation is

r = a \cos^3 \frac{\theta}{2}.

When \theta=0, r=a; when \theta is < \pi, r is positive; when \theta = \pi, r=0; and the same is true in a reverse order between \pi and 2\pi. The curve, therefore, starts at its greatest distance from the origin, and returns to the origin by having positive radii throughout a whole circumference—a portion of it accordingly lies to the left of the axis of y. The curve is in the shape of a heart, thus: O being the origin; OA=a.

Figure 13: A graph of a cardioid curve. It is heart-shaped, symmetric about the horizontal axis. The origin is labeled O, and the point of maximum distance from the origin is labeled A. The curve crosses the horizontal axis at the origin and at point A.
Fig. 13.

Many curves, whose equations are presented between linear co-ordinates, have their general form, and some of their properties, determined most readily by converting the given equation into a polar equation, as in the following example:—

36. i. \quad x^4 - ax^2y + ay^2 = 0.

Let x=r \cos \theta, y=r \sin \theta; then the equation gives r = a \frac{\sin \theta}{\cos^3 \theta} (\cos^2 \theta - \sin^2 \theta).

When \theta=0, r=0; when \theta < \frac{\pi}{4}, r is positive; when \theta = \frac{\pi}{4}, r=0; hence there is an oval in the first octant, having its extremity at the origin.

When \theta > \frac{\pi}{4} < \frac{\pi}{2}, r is negative; when \theta = \frac{\pi}{2}, r is infinite; hence there is no branch of the curve in the second octant, but one extending back from the origin to infinity in the sixth octant.

When \theta > \frac{\pi}{2} < \frac{3\pi}{4}, r is negative; when \theta = \frac{3\pi}{4}, r=0; hence there is no branch of the curve in the third octant, but a branch returning from infinity to the origin in the seventh.

When \theta > \frac{3\pi}{4} < \pi, r is positive; when \theta = \pi, r=0; hence there is an oval in the fourth octant, having its extremity at the origin. The maximum radius vector occurs at about 30. The curve is therefore in the annexed form.

37. These examples will suffice to illustrate the general determination of the form of a curve from its equation. We have next to discuss the determination of the properties of curves from their equations. This we shall do very briefly, confining ourselves to curves of the second degree. As a preliminary it will be requisite to point out the method employed to transfer our reference from one system of co-ordinates to another. This method is called

Figure 14: A graph of a complex curve with multiple loops, resembling a four-leaf clover or a four-petaled flower. The loops are symmetric about both the horizontal and vertical axes. The origin is the center of the figure.
Fig. 14.

38. It is supposed that the equation to a curve referred to a certain system of co-ordinates x, y, is given; and it is required to determine what its equation becomes when referred to another system of co-ordinates x', y'. The problem obviously resolves itself into the determination of the values of x and y in terms of x' and y', and the substitution of the latter in place of the former. The formulae are thus obtained.

39. 1°. If the new axes are parallel to the old, the origin alone being changed—it is evident that nothing is required but to write x' + a in place of x, and y' + b in place of y; where a and b are the co-ordinates of the new origin referred to the old.

40. 2°. Suppose the origin unchanged, and both the old and new axes rectangular, the axis of x' being inclined to that of x by the angle \theta. Let OM = x, MP = y, ON = x', NP = y'. Draw NR, NQ parallel to Oy and Ox respectively;

Figure 15: A geometric diagram showing a coordinate system with axes OX and OY. A point P is plotted. A new coordinate system with axes OX' and OY' is shown, where OX' is inclined at an angle theta to OX. The new coordinates of P are x' and y'. Auxiliary lines NR and NQ are drawn from point N to the OX and OY axes respectively, forming a rectangle with P and Q.
Fig. 15.

then x = OR - QN = x' \cos \theta - y' \sin \theta,
y = NR + PQ = x' \sin \theta + y' \cos \theta.

41. 3°. Suppose the origin to be unchanged; and neither the old nor the new axes to be necessarily rectangular.

Let OM = x, MP = y, ON = x', NP = y'. Draw ME, NF perpendicular to Oy, and let NG be parallel to Oy and meet EM produced in G; then ME = NF - GM, or x \sin x'Oy = x' \sin x'Oy - y' \sin y'Oy. Similarly, by drawing perpendiculars from P and N on Ox, we get

Figure 16: A geometric diagram showing a coordinate system with axes OX and OY. A point P is plotted. A new coordinate system with axes OX' and OY' is shown, where OX' is inclined at an angle theta to OX. The new coordinates of P are x' and y'. Auxiliary lines ME, NF, and NG are drawn to show the relationship between the coordinates in the two systems.
Fig. 16.
y \sin y'Ox = x' \sin x'Ox + y' \sin y'Ox.

42. 4°. When both the origin and the direction of the axes are to be changed, we have only to unite the processes of No. 1 and Nos. 2 and 3 to effect the transformation.

43. 5°. To obtain a polar equation, let OP = r;

\text{then } x = r \frac{\sin OPM}{\sin PMx} = r \frac{\sin POy}{\sin xOy} y = r \frac{\sin POM}{\sin PMx} = r \frac{\sin POx}{\sin xOy}

Properties of Curves of the Second Degree, as deduced from the general equation.

The general equation of the second degree is
Ay^2 + 2Bxy + Cx^2 + 2Dy + 2Ex + F = 0.

44. PROP. I.—No straight line can cut a curve of the second degree in more than two points.

Let y = mx + n be the equation to a straight line, then by substituting this value of y in the given equation, we have a quadratic for the determination of the values of x at the points where the co-ordinates are common to it and to the straight line. A similar process gives a quadratic equation in y. Consequently there are but two solutions, and therefore but two points of intersection.

By referring to the equations to the conic sections given above, it will be seen that they are curves of the second degree.

45. PROP. II.—Admitting that the above equation represents a conic section, it is required to determine the particular one.

If we solve the equation with respect to y, we obtain

Ay = -(Bx + D) \pm \sqrt{(B^2 - AC)x^2 + 2(BD - AE)x + D^2 - AF}.

Now, I. If B^2 - AC be negative, this value of y is impossible when x is infinite; which shows that the curve does not extend to an infinite distance. It is therefore a circle or an ellipse, according as C is equal to A or not. The ellipse, however, may be simply a point, and the equation may be impossible.

II. If B^2 - AC be positive, y has two real roots when x is infinite, whether x be positive or negative. The curve has consequently four infinite branches as in the hyperbola or in two intersecting straight lines.

III. If B^2 - AC = 0; then if BD - AE is positive, y will be possible when x is positive and infinite, but impossible when x is negative, and vice versa. The curve is consequently a parabola. If BD - AE = 0, the equation represents two straight lines or one, or is impossible.

IV. If the quantity under the radical is a complete square, i. e., if (B^2 - AC)(D^2 - AF) = (BD - AE)^2 the equation represents two straight lines; for it is the product of two simple equations.

46. PROP. III.—To find the centre of the curve.

The centre is that point which bisects every chord which can be drawn through it. Let a, b be the co-ordinates of the centre; x', y' the co-ordinates when the centre is the origin; then (Art. 39) we have x = x' + a, y = y' + b; whence A(y' + b)^2 + 2B(x' + a)(y' + b) + C(x' + a)^2 + 2D(y' + b) + 2E(x' + a) + F = 0.

Now when y' = 0, this equation must give two values of x', equal and with opposite signs, because the chord of x' is bisected at the centre. Hence their sum is equal to 0;

\text{or } Bb + Ca + E = 0;
\text{similarly, } Ab + Ba + D = 0;
\text{whence } a = -\frac{BD - AE}{B^2 - AC}, \quad b = -\frac{BE - CD}{B^2 - AC},

which are the co-ordinates of the centre.

In the case of the parabola these co-ordinates are infinite, for (Art. 45) B^2 - AC = 0; hence we may say that the parabola has no centre. In analysis, however, it is desirable to regard the centre as existing at an infinite distance.

47. PROP. IV.—To find the locus of the middle points of parallel chords.

Let a, b be the co-ordinates of one of those middle points, and let the origin be transferred to that point by writing x' + a, y' + b for x and y. Let also y' = mx' be the equation to this chord; then the points in which it intersects the curve will be those for which x' and y' are the same in the equation to the curve and to the chord. Hence

A(mx' + b)^2 + 2B(x' + a)(mx' + b) + C(x' + a)^2 + 2D(mx' + b) + 2E(x' + a) + F = 0

is the equation for determining the values of x' at the points of section; but since these are by hypothesis equal and with opposite signs, the co-efficient of x' must be equal to 0;

\text{therefore } Amb + Bb + Bma + Ca + Dm + E = 0.

Now m remains the same for all chords which are parallel. This equation is therefore a simple equation between a and b; consequently if a and b be considered as the co-ordinates of middle points generally, the equation which connects them is the equation to a straight line. The locus of the middle points of all parallel chords is therefore a straight line.

Analytical Geometry. 48. Every straight line which bisects a system of parallel chords is called a diameter, and the chords themselves are called ordinates to that diameter.

49. COR.—From the definition of a centre it is evident that every diameter passes through it.

In the case of the parabola, which has no finitely situated centre, we observe that B^2 = AC. Now the equation to the diameter (Art. 47) is

Bb + Ca + m(Ab + Ba) + E + mD = 0;
\text{or } Bb + Ca + m\left(\frac{B^2}{C}b + Ba\right) + E + mD = 0;
\text{or } \left(1 + \frac{mB}{C}\right)(Bb + Ca) + E + mD = 0;
\text{i.e. } Bb + Ca + \frac{C}{1 + mB}(E + mD) = 0;

in which the co-efficients of the co-ordinates a and b are independent of m, which shows (Art. 8) that all diameters of the parabola are parallel to one another.

50. PROP. V.—If two diameters of a curve of the second degree be such that one of them bisects all chords parallel to the other, then the latter also will bisect all chords parallel to the former.

By Art. 47 the equation to the line which bisects all chords parallel to the line whose equation is y = mx, is

(Am + B)b + (Bm + C)a + Dm + E = 0,
\text{or } y + \frac{Bm + C}{Am + B}x + \frac{Dm + E}{Am + B} = 0,

by writing y and x for the symbols which stand for the general phrases latitude and longitude of a point in the line. Let this be abbreviated by y = m'x + \dots,

\text{where } m' = -\frac{Bm + C}{Am + B}.

In the same manner the diameter which bisects all chords parallel to y = m'x is y = m''x;

\begin{aligned} \text{where } m'' &= -\frac{Bm' + C}{Am' + B} \\ &= -\frac{B^2m + BC}{Am + B} + C \\ &= -\frac{ABm + AC}{Am + B} + B \\ &= m \end{aligned}

i.e. (Art. 8), this diameter is parallel to the original chord; hence the truth of the proposition. Diameters so related to each other are called conjugate diameters.

51. PROP. VI.—If through any point O two chords be drawn, meeting the curve in the points P, Q, and R, S, respectively; then, the ratio of the rectangle OP \cdot OQ, to the rectangle OR \cdot OS, is a ratio which is the same whatever be the point O, provided the direction of the chords remain unchanged.

Let the co-ordinates of O be a and b; the polar radius through O = r; then (Art. 43) we have

\begin{aligned} x &= r \frac{\sin POy}{\sin xOy} + a, & y &= r \frac{\sin POx}{\sin xOy} + b \\ &= mr + a \text{ suppose} & &= nr + b, \end{aligned}

where m and n depend on the direction of the radius or chord.

The general equation becomes, by substitution, A(nr + b)^2 + 2B(mr + a)(nr + b) + C(mr + a)^2 + 2D(nr + b) + 2E(mr + a) + F = 0; which gives two values of r, viz. OP, OQ. Their product is the last term of the equation, viz.

\frac{Ab^2 + 2Bab + Ca^2 + 2Db + 2Ea + F}{An^2 + 2Bmn + Cm^2}

similarly the product OR \cdot OS is

\frac{Ab^2 + 2Bab + Ca^2 + 2Db + 2Ea + F}{An^2 + 2Bmn + Cm^2}.

Consequently OP \cdot OQ : OR \cdot OS :: An^2 + 2Bmn + Cm^2 : An^2 + 2Bmn + Cm^2;

a ratio which is independent of a and b, and therefore of the position of the point O. If O' be any other point, and O'P' be parallel to OP, O'R' to OR, &c.; then OP \cdot OQ : OR \cdot OS :: O'P' \cdot O'Q' : O'R' \cdot O'S.

52. COR. 1.—If O' be the centre; O'P' = O'Q', O'R' = O'S; then OP \cdot OQ : OR \cdot OS :: O'P'^2 : O'R'^2. That is, if two chords intersect one another, the rectangles by their segments are to one another as the squares of the diameters parallel to them respectively.

53. COR. 2.—O' being still the centre, let O'O be the diameter of which PQ is the ordinate; and let RS and also R'S' pass through O' and coincide with one another; then OP^2 : OR \cdot OS :: O'P'^2 : O'R'^2; or the square of the ordinate is to the rectangle by the abscissas, as the square of the diameter which is parallel to the former to the square of that which passes through the latter.

54. In the case of the parabola this proposition is inapplicable; for the diameter and the chord parallel to it are both infinite. To determine the corresponding ratio for this case, let the axes be transformed to x', y' such that the axis of x' is parallel to the diameter, and the axis of y' to a bisected chord. Let also the origin be on the curve—the equation will then assume the form Ay'^2 + 2Ex' = 0; for C = 0; because when y = 0 there must be only one value of x', viz. x' = 0; but B^2 = 4AC, \therefore B = 0; and since the two values of y are equal and with opposite signs we must have D = 0; lastly, since the origin is on the curve we must have F = 0. The equation in this form shows that the abscissas are to one another as the squares of the ordinates.

The theorems contained in this second corollary constitute the fundamental properties of the conic sections, and are the same as demonstrated in the treatise on that subject. (Arts. i. 12, ii. 13, iii. 12.)

55. PROP. VII.—To find the equation to the tangent.

The tangent is that line to which a line cutting the curve in two points continually approaches as its limit, as the points of section approach to each other.

The equation to a line which meets the curve in the two points x'y', x''y'' is

y - y' = \frac{y' - y''}{x' - x''}(x - x') \quad (\text{Art. 8, Cor. 2.})

Now Ay'^2 + 2Bx'y' + Cx'^2 + 2Dy' + 2Ex' + F = 0 \dots \dots \dots (1) and Ay''^2 + 2Bx''y'' + Cx''^2 + 2Dy'' + 2Ex'' + F = 0;

by subtraction,

\begin{aligned} A(y'^2 - y''^2) + B\{x'(y' - y'') + y'(x' - x'') + x''(y' - y'') \\ + y''(x' - x'')\} + C(x'^2 - x''^2) + 2D(y' - y'') \\ + 2E(x' - x'') = 0; \end{aligned}
\text{whence } \frac{y' - y''}{x' - x''} = -\frac{B(y' + y'') + C(x' + x'') + 2E}{A(y' + y'') + B(x' + x'') + 2D};

and the equation to the cutting line is

y - y' = -\frac{B(y' + y'') + C(x' + x'') + 2E}{A(y' + y'') + B(x' + x'') + 2D}(x - x').

The equation to the tangent is derived from this by writing y' for y'' and x' for x''. It is therefore

y - y' = -\frac{By' + Cx' + E}{Ay' + Bx' + D}(x - x') \dots \dots \dots (2)

Those who are familiar with the differential calculus will obtain this result at once from the equation

y - y' = \frac{dy'}{dx'}(x - x').

If we multiply out equation (2), and substitute for Ay'^2 +

Analytical Geometry. 2Bx'y' + Cx'^2 + Dy' + Ex' its value -Dy' - Ex' - F from equation (1), we shall have

Axy' + B(xy' + x'y) + Cxx' + D(y + y') + E(x + x') + F = 0 as the equation to the tangent. The equation to the tangent is therefore to be got from the equation to the curve by writing xx' for x^2, yy' for y^2, x + x' for 2x, y + y' for 2y, and xy + xy' for 2xy; or by changing one of the x's into x', and one of the y's into y'.

56. COR.—Since the equation to the tangent is symmetrical in x and x', y and y', if we abbreviate it by \phi(x, y, x', y'), we shall have the equation \phi(x, y, x', y') = \phi(x', y', x, y); x and y being interchangeable with x' and y'.

57. PROP. VIII.—To find the equation to the straight line which joins the points of contact of two tangents, real or imaginary.

Abbreviate the equation to the curve by f(x, y) = 0, and to the tangent by \phi(x, y, x', y') = 0.

Let X, Y be the co-ordinates of the point of intersection of two tangents; then the equations f(x', y') = 0, \phi(x', y', X, Y) = 0 give the values of x', y', the co-ordinates of the point of contact of the one tangent.

Also the equations f(x'', y'') = 0, \phi(x'', y'', X, Y) = 0, give the co-ordinates x'', y'' of the point of contact of the other tangent which passes through the point X, Y.

Now, of the equations constituting these respective pairs, one is a simple equation, and the other a quadratic. Each pair will therefore give two values of the variables. But each pair is the same as the other; therefore the two roots of the one are the roots of both; or x', y', x'', y'' are the roots of the equations f(x, y) = 0, \phi(x, y, X, Y) = 0.

Again, let \psi(x, y, X, Y) = 0 be the equation to the chord which passes through the points (x', y'); (x'', y'') of contact; then will x', y', x'', y'' be the roots of the equations f(x, y) = 0, \psi(x, y, X, Y) = 0.

But it has been already proved that

f(x, y) = 0, \quad \phi(x, y, X, Y) = 0

have the same roots. Moreover, one of the equations, f(x, y) = 0, is common to both pairs; therefore the other two equations must be identical; or \psi(x, y, X, Y) = 0 is the same as \phi(x, y, X, Y) = 0; i.e., the equation to the line which joins the points of contact of two tangents is of the same form as the equation to the tangent; or if the equation to the tangent at the point x', y' in the curve is \phi(x, y, x', y') = 0; the equation to the line which joins the points of contact of two tangents which meet in a point x', y', out of the curve is \phi(x, y, x', y') = 0.

58. The line which joins the points of contact of two tangents is called the polar of their point of intersection; and that point accordingly is called the pole of the line.

59. PROP. IX.—If the point B is in the polar of A, then is A also in the polar of B.

Let x', y' be the co-ordinates of A,
x'', y'' ... B.

The equation to the polar of A is \phi(x, y, x', y') = 0; but by hypothesis B(x'', y'') is a point in this line; therefore \phi(x'', y'', x', y') = 0. Hence also (Art. 56) \phi(x', y', x'', y'') = 0. But \phi(x, y, x', y') = 0 is the equation to the polar of B; the equation \phi(x', y', x'', y'') = 0 consequently shows that x', y' are the co-ordinates of a point in that line; i.e., A is a point in the polar of B.

60. COR. 1.—If any number of points be taken in the polar of A, their polars will

Figure 17: A geometric diagram showing a conic section with points A, B, C, D, E, F, G, H, I, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z. A line segment connects A and B, and another connects B and C. A third line segment connects C and D. A fourth line segment connects D and E. A fifth line segment connects E and F. A sixth line segment connects F and G. A seventh line segment connects G and H. A eighth line segment connects H and I. A ninth line segment connects I and K. A tenth line segment connects K and L. A eleventh line segment connects L and M. A twelfth line segment connects M and N. A thirteenth line segment connects N and O. A fourteenth line segment connects O and P. A fifteenth line segment connects P and Q. A sixteenth line segment connects Q and R. A seventeenth line segment connects R and S. A eighteenth line segment connects S and T. A nineteenth line segment connects T and U. A twentieth line segment connects U and V. A twenty-first line segment connects V and W. A twenty-second line segment connects W and X. A twenty-third line segment connects X and Y. A twenty-fourth line segment connects Y and Z.
Fig. 17.

all pass through A; i.e., the polars of every point in a straight line all pass through the pole of that line.

61. COR. 2.—If A and B are the poles of two lines PQ and RS which meet in O, the line AB is the polar of the point O.

For the polar of O passes through A (by the Proposition) and through B; it is therefore the straight line AB.

62. PROP. X.—To find the condition that the straight line whose equation is my + nx + p = 0 may touch a given conic section.

The equation to the conic section may, by properly selecting the co-ordinates, be thrown into one or other of the two forms,

\frac{x^2}{a} + \frac{y^2}{b} = 1 \quad \text{or} \quad \frac{2x}{a} + \frac{y^2}{b} = 1.

The tangents to these have for their respective equations (Art. 55),

\frac{x}{a} + \frac{y}{b} = 1, \quad \text{and} \quad \frac{x + x'}{a} + \frac{y}{b} = 1.

In order that the former of these may coincide with the equation my + nx + p = 0, we must have

-\frac{n}{p} = \frac{x'}{a}, \quad -\frac{m}{p} = \frac{y'}{b}.

But \frac{x'^2}{a} + \frac{y'^2}{b} = 1; whence a n^2 + b m^2 = p^2.....(1)

is the resulting condition.

In order that the latter of the above equations may coincide with the equation my + nx + p = 0, we must have

-\frac{n}{p} = \frac{1}{1 - \frac{x'}{a}}, \quad \text{and} \quad -\frac{m}{p} = \frac{y'}{1 - \frac{x'}{a}}.
\therefore \frac{x'}{a} = 1 + \frac{p}{an}, \quad \frac{y'}{b} = \frac{m}{an};

which being substituted in the equation

\frac{2x'}{a} + \frac{y'^2}{b} = 1, \quad \text{there results}
a^2 n^2 + 2 a n p + b m^2 = 0, \dots\dots\dots(2)

as the condition required.

63. PROP. XI.—Given that chords to a curve of the second degree always touch a conic section, it is required to prove that the locus of their poles is a conic section.

Let A be the conic section to which the chords are always tangents; B the curve of the second degree (a conic section) to which the chords are drawn; C the curve which is the locus of the poles of the chords to B.

Let x', y' be the co-ordinates of a point in C, the equation to the polar of this point is

\phi(x, y, x', y') = 0 \quad (\text{Art. 57}) \quad \text{or} \quad (Ay' + Bx + D)y + (By' + Cx + E)x + Dy' + Ex' + F = 0 \quad (\text{Art. 55}).

In order that this line may be a tangent to the conic section A, whose equation we shall suppose to be either

\frac{x^2}{a} + \frac{y^2}{b} = 1 \quad \text{or} \quad \frac{2x}{a} + \frac{y^2}{b} = 1,

we have to satisfy one or other of the two conditions obtained in the last proposition, viz.

Figure 18: A geometric diagram showing a conic section A and a curve of the second degree B. A line segment connects A and B. A second line segment connects B and C. A third line segment connects C and D. A fourth line segment connects D and E. A fifth line segment connects E and F. A sixth line segment connects F and G. A seventh line segment connects G and H. A eighth line segment connects H and I. A ninth line segment connects I and K. A tenth line segment connects K and L. A eleventh line segment connects L and M. A twelfth line segment connects M and N. A thirteenth line segment connects N and O. A fourteenth line segment connects O and P. A fifteenth line segment connects P and Q. A sixteenth line segment connects Q and R. A seventeenth line segment connects R and S. A eighteenth line segment connects S and T. A nineteenth line segment connects T and U. A twentieth line segment connects U and V. A twenty-first line segment connects V and W. A twenty-second line segment connects W and X. A twenty-third line segment connects X and Y. A twenty-fourth line segment connects Y and Z.
Fig. 18.

Analytical Geometry. or a(By' + Cx' + E)^2 + b(Ay' + Bx' + D)^2 = (Dy' + Ex' + F)^2 (1)
or a^2(By' + Cx' + E)^2 + 2a(By' + Cx' + E)(Dy' + Ex' + F) + b(Ay' + Bx' + D)^2 = 0 ..... (2)
as necessary to be fulfilled.

If the requisite one of these relations between x' and y' hold true, the polar to every point in C will touch A. But these conditions are both expressed in the form of a quadratic equation between x' and y'. Hence the curve C is a curve of the second degree or a conic section.

64. PROP. XII.—Given that C is generated by A through the intervention of B, as in the last proposition, to prove that A would be generated by C through the intervention of the same curve B.

Let two tangents be drawn to A, forming chords to B, and let the poles of those chords be C and C' in the curve C: then (Art. 61) the point of intersection of those tangents is the pole of CC' (a chord in C). But as the tangents become indefinitely near each other, their point of intersection tends to become the point A in the curve A; and the points C, C' also tend to become indefinitely near each other, or the chord CC' tends to become a tangent. Hence the point A on the curve A is the pole of the tangent to a point C on the curve C.

65. The curves A and C are therefore reciprocal, and the process which employs this method of demonstration is termed the method of reciprocal polars. We shall confine ourselves to a single application of this method, that of connecting two theorems relative to the conic sections which are known as PASCAL'S and BRIANCHON'S theorem respectively.

Pascal's Theorem.

66. PROP. XIII.—If any hexagon be inscribed in a conic section, and the opposite sides be produced to meet in three points, those points are in a straight line.

Let ABCDEF be a hexagon inscribed in a conic section, and let the opposite sides produced meet in the

Geometric diagram illustrating Pascal's Theorem. A conic section is shown with an inscribed hexagon ABCDEF. The opposite sides are extended to meet at three points: G (intersection of AB and DE), H (intersection of BC and EF), and K (intersection of CD and FA). These three points G, H, and K are shown to lie on a single straight line, which is the Pascal line.

Fig. 18.

points G, H, and K; viz., AB and DE in G; BC and EF in H; CD and FA in K: then the points G, H, and K

are in a straight line. Let u=0, v=0, w=0, be three simple equations between x and y, each multiplied by an arbitrary constant, as in Art. 7; and let u=0 (1) be the equation to the line AB, v=0 (2) to the line CD, and w=0 (3) to the line EF.

Now since u, v, w, involve x and y, u^2, v^2, w^2, &c., will involve x^2, y^2, &c., consequently

u^2 + v^2 + w^2 - (\lambda + \frac{1}{\lambda})uv - (\mu + \frac{1}{\mu})vw - (\nu + \frac{1}{\nu})uw = 0 \dots \dots \dots (4)

is an equation between x, y, x^2, y^2, &c., containing six arbitrary constants; and is therefore the general equation of the second degree which represents any conic section.

At the points A and B, where the straight line represented by equation (1) intersects the conic section represented by (4), the same values of x and y render both equations identical, or u is the same in fact as well as in form in both equations:

We must have, therefore,

v^2 + w^2 - (\lambda + \frac{1}{\lambda})vw = 0,
\text{or } v = \lambda w \text{ and } v = \frac{1}{\lambda} w

at those points respectively. Similarly at the points D and C we must have u = \mu w, u = \frac{1}{\mu} w respectively, and at the points E and F, u = \nu w and u = \frac{1}{\nu} w. Hence the points are thus determined, viz.:

A \text{ by the equations } u = 0, v = \lambda w \dots \dots \dots (5)
B \dots \dots u = 0, v = \frac{1}{\lambda} w \dots \dots \dots (6)
C \dots \dots v = 0, u = \frac{1}{\mu} w \dots \dots \dots (7)
D \dots \dots v = 0, u = \mu w \dots \dots \dots (8)
E \dots \dots w = 0, u = \nu w \dots \dots \dots (9)
F \dots \dots w = 0, u = \frac{1}{\nu} w \dots \dots \dots (10)

Let u = Av + Bw be the equation to the line which passes through the points B and C; then, by (6) we must have 0 = \frac{A}{\lambda} + B; and by (7) \frac{1}{\mu} = B; consequently

u = \frac{1}{\mu} (-\lambda v + w) \dots \dots \dots (11)

is the equation to the line BC. Similarly u = \nu v + \mu w (12)

is the equation to the line DE, and u = \frac{1}{\nu} (v - \lambda w) (13) is

the equation to the line FA.

Let Au + Bv + Cw = 0 be the equation to GK.

This equation and the equations to AB and ED must be simultaneously satisfied at the point G. Combining then

(1) and (12) with this equation we get \frac{\mu}{C} = \frac{\nu}{B}.

In like manner the equation must be satisfied simultaneously with those to AF and CD, at the point K. The equations (2) and (13) combined with it give \frac{\nu}{A} = \frac{\lambda}{C}, whence

A = \frac{1}{\lambda}, B = \frac{1}{\mu}, C = \frac{1}{\nu}; and the equation to the line GK becomes

\frac{u}{\lambda} + \frac{v}{\mu} + \frac{w}{\nu} = 0 \dots \dots \dots (14).

Again, let Au + Bv + Cw = 0 be the equation to the line GH. The point G gives as before \frac{\mu}{C} = \frac{\nu}{B}; at the point H the equation must be satisfied simultaneously with the equa-

Analytical Geometry. tions to BC and EF. Combining (3) and (11) with it, we get \frac{\mu}{A} = \frac{\lambda}{B}; whence we obtain A = \frac{1}{\lambda}, B = \frac{1}{\mu}, C = \frac{1}{\nu}; and

the equation to GH is \frac{u}{\lambda} + \frac{v}{\mu} + \frac{w}{\nu} = 0, the same as the equation to GK. Hence GH and GK are in the same straight line.

67. CON.—It is evident that the demonstration does not require any order of position amongst the points, or, in other words, that the points are interchangeable. Consequently, if for hexagon we read six points, and admit every variety of modes of joining them, we shall obtain a great number (sixty) of different straight lines in which three points of intersection of joining lines lie.

Brianchon's Theorem.

68. PROP. XIV.—If any hexagon be described about a conic section, the three diagonals which join opposite angles meet in a point.

Let two tangents be drawn to a conic section A as in Art. 63, meeting in the point P, and let their poles in the conic section C be a, b; then (Art. 61) P is the pole of the line ab. The same is true of any other pair of tangents; consequently, if six tangents be drawn to A forming a hexagon about it, their points of intersection will be the poles of a hexagon in C.

Let us designate the angles of the hexagon described about A by P, Q, R, S, T, U; and the sides of the hexagon described in C to which they are respectively poles by p, q, r, s, t, u.

Let p and s meet in G; q and t in H, and r and u in K; then, by the last proposition, G, H, and K are in a straight line.

Now (Art. 61) G is the pole of PS, H of QT, and K of RU; and since G, H, and K are in a straight line, their polars PS, QT, RU pass through the pole of that line (Art. 60); or meet in a point.

SECTION III.—DEDUCTION OF PROPERTIES OF CURVES FROM THEIR EQUATIONS AND KNOWN PROPERTIES.

We propose in this section to deduce some of the more important properties of the conic sections from their equations, combined with their known geometrical figures. The axes of co-ordinates will be supposed rectangular unless otherwise expressed.

1. The Straight Line.

69. PROP. I.—To find the equation to a straight line which shall be perpendicular to a given straight line.

Let y = ax + b be the equation to the given straight line. y = px + q that of the required line.

If \theta, \varphi be the angles in which those lines respectively cut the axis of x; it is evident that the condition imposed requires that

\varphi = \frac{\pi}{2} + \theta;
\therefore \tan \varphi = -\cot \theta = -\frac{1}{\tan \theta};
\text{or } p = -\frac{1}{a} \text{ (Art. 6);}

hence y = -\frac{1}{a}x + q is the equation required.

70. PROP. II.—To find the length of the perpendicular from a given point on a given line.

Let x', y' be the co-ordinates of the given point A; y = ax + b the equation to the given line PR.

Draw AP perpendicular to the given line, and let y' cut RP in E;

\begin{aligned} \text{then } AE &= AD - ED \\ &= y' - (ax' + b) \\ \text{and } AP &= AE \sin AEP = AE \cos PRM \\ &= \frac{AE}{\sqrt{1 + \tan^2 PRM}} = \frac{y' - (ax' + b)}{\sqrt{1 + a^2}} \end{aligned}

71. We may exhibit this result in a very different form by adopting the equation to a straight line given in Art. 7.

Let AP = P; then the equation to a line through A parallel to RP is y \cos \alpha - x \sin \alpha - (p + P) = 0; and since A is a point in this line,

\begin{aligned} y' \cos \alpha - x' \sin \alpha - (p + P) &= 0; \\ \text{or } P &= y' \cos \alpha - x' \sin \alpha - p; \\ &= a \text{ (Art. 7) when } x', y' \text{ are written for } x \text{ and } y. \end{aligned}

72. PROP. III.—If \alpha = 0, \beta = 0 be the equations to two straight lines, agreeably to the abbreviated notation of Art. 7; then la + m\beta = 0, or \alpha - k\beta = 0 will represent a line which passes through their point of intersection.

For the co-ordinates which render both \alpha = 0 and \beta = 0 render la + m\beta = 0, or \alpha - k\beta = 0; and are therefore co-ordinates of a point in the last line as in the other two.

73. PROP. IV.—If \alpha = 0 be the equation to the line QA, \beta = 0 to the line QB, and \alpha - k\beta = 0 to the line QC;

\text{then } k = \frac{\sin AQC}{\sin BQC}.

Let x', y' be the co-ordinates of C. Draw CA, CB perpendicular to QA, QB; then (Art. 71) CA = y' \cos \alpha - x' \sin \alpha - p.

= a, \text{ when } x', y' \text{ are written in place of the co-ordinates.}

CB = \beta, when x', y' are written for the co-ordinates. But since x', y' is a point in the line \alpha - k\beta = 0, we have

k = \frac{a}{\beta} \text{ when } x', y' \text{ are written for the co-ordinates,}
= \frac{CA}{CB} = \frac{QC \sin AQC}{QC \sin BQC} = \frac{\sin AQC}{\sin BQC}.

74. COR. 1.—The equation to the line QC is therefore \alpha \sin BQC - \beta \sin AQC = 0.

75. COR. 2.—The straight line which bisects the angle between two straight lines whose equations are \alpha = 0, \beta = 0 is \alpha - \beta = 0.

76. PROP. V.—If \alpha = 0, \beta = 0, \gamma = 0 be the equations to three straight lines, and it be possible to find three numerical quantities, l, m, n, such that la + m\beta + n\gamma shall be equal to 0; the three straight lines shall meet in one point.

At the point where two of them whose equations are \alpha = 0, \beta = 0 intersect, the co-ordinates render la + m\beta = 0. But, by hypothesis, la + m\beta + n\gamma = 0 for all co-ordinates;

Figure 20: A geometric diagram showing a line PR with points R, O, D, M. A point A is above the line. A vertical line AD is dropped from A to D on PR. A line AP is drawn from A to a point P on PR. A line AE is drawn from A to a point E on PR. A line y' is drawn from E to the y-axis. The diagram illustrates the construction for finding the perpendicular distance from point A to line PR.

Fig. 20.

Figure 21: A geometric diagram showing three lines QA, QB, and QC originating from a common point C. Line QA is horizontal. Line QB is at an angle alpha to QA. Line QC is at an angle alpha - k*beta to QA. Points A, B, and C are marked on the lines. Perpendiculars CA and CB are drawn from C to QA and QB respectively.

Fig. 21.

\therefore \pi\gamma = 0 for the co-ordinates of the point where the first and second lines meet; consequently the same co-ordinates belong to the third line; or the three meet in that point.

77. PROP. VI.—The straight lines which bisect the angles of a triangle meet in a point.

Let \alpha = 0, \beta = 0, \gamma = 0 be the equations to the sides of the triangle; \alpha - \beta = 0, \alpha - \gamma = 0, \beta - \gamma = 0 (Art. 75) are the equations to the lines which bisect the angles. But \alpha - \beta - (\alpha - \gamma) + \beta - \gamma = 0; consequently (Art. 76) these lines meet in a point.

78. PROP. VII.—The perpendiculars from the angles of a triangle on the opposite sides meet in a point.

Let the angle between the lines whose equations are \alpha = 0, \beta = 0 be denoted by (\alpha\beta), &c.; then (Art. 74) the equation to the perpendicular from the angle in which these two meet is

u = \alpha \cos(\beta\gamma) - \beta \cos(\alpha\gamma) = 0.

Similarly the equations to the other two perpendiculars are

v = \gamma \cos(\alpha\beta) - \alpha \cos(\gamma\beta) = 0,
w = \beta \cos(\gamma\alpha) - \gamma \cos(\beta\alpha) = 0.

Hence we have u + v + w = 0, therefore (Art. 76) the three lines meet in a point.

79. PROP. VIII.—If there be two triangles such that the perpendiculars from the angles of the one on the sides of the other meet in a point, then the perpendiculars from the angles of the latter on the sides of the former will also meet in a point.

Let the equations to the sides of the former triangle be \alpha = 0, \beta = 0, \gamma = 0; and of the latter \alpha' = 0, \beta' = 0, \gamma' = 0. Let also (\alpha\beta) denote the angle between the lines \alpha = 0, \beta = 0; (\alpha'\beta') between the lines \alpha' = 0, \beta' = 0, &c. Then (Art. 74) the equation to the perpendicular from the point (\alpha\beta) on the line \gamma' = 0 is \alpha \cos(\beta\gamma') - \beta \cos(\alpha\gamma') = 0....(1) and the equation to the perpendicular from the point (\alpha\gamma) on the line \beta' = 0 is \alpha \cos(\gamma\beta') - \gamma \cos(\alpha\beta') = 0....(2) and from (\beta\gamma) on \alpha' = 0, \beta \cos(\gamma\alpha') - \gamma \cos(\beta\alpha') = 0....(3) Now at the point where these three lines meet, \alpha is the same in (1) and (2), \beta in (1) and (3), and \gamma in (2) and (3). Hence by elimination between (1) and (3), we get

\alpha \cos(\beta\gamma') \cos(\gamma\alpha') - \gamma \cos(\beta\alpha') \cos(\alpha\gamma') = 0;

which, when combined with (2), gives

\cos(\beta\gamma') \cos(\gamma\alpha') \cos(\alpha\beta) = \cos(\beta\alpha') \cos(\alpha\gamma') \cos(\gamma\beta') \dots\dots(4)

Now, if we change \alpha into \alpha', \beta into \beta', \gamma into \gamma', and conversely, we obtain the equations to the perpendiculars from the angles of the latter triangle on the sides of the former. At the point where the first and third of these lines intersect, we shall have, as before,

\alpha' \cos(\beta'\gamma') \cos(\gamma'\alpha') - \gamma' \cos(\beta'\alpha') \cos(\alpha'\gamma') = 0;

and the equation to the second line is

\alpha' \cos(\gamma'\beta') - \gamma' \cos(\alpha'\beta') = 0.

But because, by equation (4),

\cos(\beta'\gamma') \cos(\gamma'\alpha') \cos(\alpha'\beta) = \cos(\beta'\alpha') \cos(\alpha'\gamma') \cos(\gamma'\beta), the same values of \alpha' and \gamma' satisfy both these equations. Hence the three lines meet in one point.

2. The Circle.

We shall confine ourselves to two properties only of the circle, both because of their more simple geometric deduction, and because they are included in the properties of the ellipse.

80. PROP. I.—If TPQ be a tangent to a circle; CT, BQ perpendiculars to the diameter from its extremities; then the rectangle PT.PQ = \text{rad}^2.

When the centre is the origin, the equation to the circle is x^2 + y^2 = a^2 (Art. 10), and that of the tangent is xx' + yy' = a^2 (Art. 55).

\begin{aligned} \text{Hence } \quad & ax' + BQ \cdot y' = a^2 \\ & - ax' + CT \cdot y' = a^2 \\ \therefore CT \cdot BQ \cdot y'^2 & = a^2 (a^2 - x'^2) \\ & = a^2 y'^2 \end{aligned}
\begin{aligned} \text{or } \quad & CT \cdot BQ = a^2 \\ \text{but } CT = PT, BQ = PQ, \therefore PT \cdot PQ & = a^2. \end{aligned}

81. PROP. II.—If through a fixed point chords are drawn to a circle, and tangents are drawn at the extremities of those chords, the locus of the points of intersection of the tangents is a straight line.

Let b, c be the co-ordinates of the fixed point, x', y' the co-ordinates of a point in which two tangents to the circle intersect one another; then (Art. 57) the equation to the chord which joins the points of contact is xx' + yy' = a^2. But, by hypothesis, b, c are co-ordinates of a point in this line, \therefore bx' + cy' = a^2. Now this is a simple equation between x' and y'. Hence the truth of the proposition.

3. The Parabola.

82. PROP. I.—To find the latus rectum of the parabola.

The latus rectum is the ordinate to the axis drawn through the focus.

By Art. 12 the equation to the parabola is y^2 = 4ax. Now, when x = a, y is half the chord through the focus; \therefore that half-chord2 = 4a^2, or the latus rectum = 4a.

83. PROP. II.—To find the subtangent of the parabola.

The subtangent is the portion of the diameter included between the ordinate and the tangent.

Let PT be the tangent meeting the axis in T; MT is the subtangent.

The equation to the tangent PT is (Art. 55) yy' = 2a(x + x').

Now, at the point T, y = 0, \therefore x = -x', or AT = AM; hence the subtangent is double the abscissa.

84. COR.—Since AT = AM and AF = AD; by addition, FT = DM = PQ = FP; \therefore \angle FPT = \angle FTP = \angle QPT, or the tangent bisects the angle between two lines drawn from the point of contact, the one to the focus, the other perpendicular to the directrix.

This is the property of the tangent employed in the treatise on CONIC SECTIONS, to which the reader is referred for the geometrical properties to which it leads.

85. PROP. III.—To find the equation to the normal of the parabola.

The normal is the straight line which is perpendicular to the tangent at the point of contact.

Let PT be the tangent at the point P, PG perpendicular to PT is the normal.

The equation to PT is

yy' = 2a(x + x'), \text{ or } y = \frac{2a}{y'} x + \frac{2ax'}{y'};

and the equation to a line perpendicular to this is (Art. 69)

y = -\frac{y'}{2a} x + q.
Figure 22: A geometric diagram illustrating the subtangent of a parabola. A parabola opens to the right with its vertex at the origin. The axis is the x-axis. A point P is on the parabola. A tangent line PT is drawn from P, intersecting the x-axis at T. A vertical line segment PQ is drawn from P to the x-axis at Q. A diameter line passes through P and Q, intersecting the x-axis at M. The subtangent is the segment MT on the x-axis. Points D, A, F, M, G are marked on the x-axis. The diagram shows the relationship between the tangent, the diameter, and the subtangent.

Analytical Geometry. Now the point P, whose co-ordinates are x, y, is a point in this line; therefore

y = -\frac{y}{2a}x + q,

and by subtraction y - y' = -\frac{y}{2a}(x - x'), which is the equation to the normal.

86.—COR. At the point G, y = 0, x = AG. Hence AG = x + 2a = AM + 2a; \therefore MG = 2a.

The line MG is called the subnormal; and it follows that the subnormal is equal to half the latus rectum.

87. PROP. IV.—The perpendicular from the focus on the tangent intersects the tangent in the axis of y.

The equation to the tangent is

\begin{aligned} yy' &= 2a(x + x') \\ &= 2ax + \frac{y^2}{2} \end{aligned}
\text{or } y' \left( y - \frac{y'}{2} \right) = 2ax; \dots \dots \dots (1)

and the equation to the perpendicular from F on the tangent is

\begin{aligned} y &= -\frac{y'}{2a}(x - a) \\ &= -\frac{y'x}{2a} + \frac{y'}{2} \end{aligned}
\text{or } y - \frac{y'}{2} = -\frac{y'x}{2a}; \dots \dots \dots (2)

At their point of section x and y are the same in both. Now if x be not 0, y - \frac{y'}{2} is positive in equation (1) and negative in equation (2), or vice versa, which is impossible; \therefore x = 0, or the point of intersection is in the axis of y.

88. COR.—FP : FY :: FY : FA,

\text{or } FP = \frac{FY^2}{FA} = \frac{FY^2}{FA^2} FA = \frac{FA}{\sin^2 T}

89. PROP. V.—To find the locus of the intersection of the tangent with the perpendicular on it from the vertex.

The equation to the tangent is yy' = 2a(x + x'), \dots \dots (1) and the equation to the perpendicular on it from the vertex is y = -\frac{y'}{2a}x; \dots \dots \dots (2)

Also the equation to the parabola is y^2 = 4ax', \dots \dots (3)

From equation (2), y = -2a\frac{y'}{x}, and hence, from equation (1)

2ax' = -\frac{2ay^2}{x} - 2ax. Substituting these values in (3), there is obtained

\frac{4a^2y^2}{x^2} = -\frac{4ay^2}{x} - 4ax
\text{or } y^2 = -\frac{x^3}{a+x};

which shows (Art. 19) that the locus is a cissoid, the diameter of whose generating circle is AD.

90. PROP. VI.—To find the equation to the parabola when the axes are any diameter and the tangent at its extremity.

Let PN be the diameter parallel to AM; QN the ordinate parallel to the tangent at P; x, y the co-ordinates of P; x', y' of Q referred to the axis; x'', y'' the co-ordinates PN, NQ referred to the diameter PN and the tangent PN.

Figure 22: A geometric diagram showing a parabola with vertex A and focus F. A diameter PN is drawn parallel to the axis AM. A point P is on the parabola, and a point Q is on the diameter. QN is an ordinate parallel to the tangent at P. The diagram shows the relationship between the co-ordinates of P and Q referred to the axis and the diameter.
Fig. 22.

Hence, x = x' + x'' + y' \cos T, y = y' + y'' \sin T;

therefore the equation y^2 = 4ax becomes

(y' + y'' \sin T)^2 = 4a(x' + x'' + y' \cos T), \text{or } y'^2 + 2y'y'' \sin T + y''^2 \sin^2 T = 4ax' + 4ax'' + 4ay' \cos T.

Now \tan T = \frac{2a}{y'} (Art. 6); \therefore 2y'y'' \sin T = 4ay'' \cos T; and y'^2 = 4ax'; hence the equation is reduced to y''^2 \sin^2 T = 4ax''.

But \frac{4a}{\sin^2 T} = 4FP (Art. 88); hence y''^2 = 4FPx'' is the equation required.

The equation when the curve is referred to any diameter and its bisected chords is consequently of the same form as the equation when the curve is referred to the axis. The conclusions arrived at in the one case are very easily adapted to the other.

91. PROP. VII.—The semi-latus-rectum is an harmonic mean between the segments of any chord drawn through the focus.

Let PFR be a chord through the focus; then (Art. 13),

\frac{1}{FP} = \frac{1}{2a} (1 - \cos PFM);
\text{similarly } \frac{1}{FR} = \frac{1}{2a} (1 - \cos RFM).

Now, \cos PFM + \cos RFM = 0; \therefore \frac{1}{FP} + \frac{1}{FR} = \frac{2}{2a}, which proves the proposition.

4. The Ellipse.

92. PROP. I.—If a circle be described about the axis major, then ordinates to the ellipse and the circle to the same abscissa, have to one another the proportion of the axis minor to the axis major.

Figure 24: A geometric diagram showing an ellipse with major axis AB and minor axis CD. A circle is inscribed within the ellipse, touching it at the vertices A and B. A point M is on the major axis AB. A vertical line segment MPQ is drawn from M, where P is on the ellipse and Q is on the circle. The diagram illustrates the relationship between the ordinates of the ellipse and the circle for a given abscissa.
Fig. 24.

Let MPQ be an ordinate to the abscissa CM; then

MP^2 = \frac{b^2}{a^2}(a^2 - x^2) \text{ (Art 14),}
MQ^2 = a^2 - x^2 \text{ (Art. 10);}
MP^2 : MQ^2 :: b^2 : a^2,
MP : MQ :: b : a.

93. PROP. II.—To find the subtangent of the ellipse.

The equation to the tangent PT is a^2yy' + b^2xx' = a^2b^2. At the point T, y = 0; \therefore xx' = a^2, or CT.CM = CA2; whence the subtangent

MT = CT - CM = \frac{CA^2}{CM} - CM = \frac{CA^2 - CM^2}{CM}.

94. COR.—If a tangent be drawn to the circle at Q, it will cut the axis in the same point T, for CT is independent of b.

95. PROP. III.—To find the value of the subnormal.
The equation to the tangent being a^2 y y' + b^2 x x' = a^2 b^2, the equation to the normal PG will be
y - y' = \frac{a^2 y'}{b^2 x'} (x - x') \quad (\text{Art. 69}).
Now, at the point G we have y = 0;
\therefore CG = x' - \frac{b^2 x'}{a^2} = e^2 x' = e^2 CM.
96. PROP. IV.—The normal bisects the angle between the two focal distances.
For, retaining the letters placed at the foci in Art. 14, we have
FG = FC + CG = ae + e^2 x';
\text{and } SG = SC - CG = ae - e^2 x'.
\text{Also } SP = a - ex' \quad (\text{Art. 15}), \text{ and therefore}
FP = a + ex'; \text{ whence}
FG : SG :: FP : SP,
and (Euc. vi. 3) the angle FPS is bisected by the line PG.
97. COR.—Hence also the tangent bisects the angle between one of the focal distances and the other produced.
98. PROP. V.—To find the locus of the intersection of the tangent with the perpendicular on it from the focus.
If we write m = \frac{b^2 x'}{a^2 y'}, we shall have as the equation to the tangent, y + mx = \frac{b^2}{y'}.
\text{Now } \left(\frac{b^2}{y'}\right)^2 = m^2 \left(\frac{a^2}{x'}\right)^2 = \frac{m^2 a^2}{1 - \frac{y^2}{b^2}};
hence \left(\frac{b^2}{y'}\right)^2 - b^2 = m^2 a^2, and y + mx = \sqrt{b^2 + m^2 a^2} is the equation to the tangent.
Also the equation to the perpendicular on it from the focus is, y = \frac{1}{m}(x - ae); or my - x = -ae. Squaring the equations and adding them, we get
(1 + m^2)(x^2 + y^2) = b^2 + m^2 a^2 + a^2 e^2,
= (1 + m^2) a^2;
\therefore x^2 + y^2 = a^2;
or the locus required is the circle described about the major axis.
99. PROP. VI.—The rectangle by the two perpendiculars from the foci on the tangent is equal to the square of the semi-axis minor.
The length of the perpendicular from a point whose co-ordinates are x, y, on a straight line whose equation is y = -mx + c is (Art. 70) \frac{y_1 + mx_1 - c}{\sqrt{1 + m^2}};
Now, the co-ordinates of S are x_1 = ae, y_1 = 0; hence the perpendicular from S on the tangent is equal to
\frac{mae - c}{\sqrt{1 + m^2}}, \text{ where } c = \sqrt{b^2 + m^2 a^2}.
In the same way the length of the perpendicular from F on the tangent is \frac{-mae - c}{\sqrt{1 + m^2}}; consequently their rectangle is
\frac{c^2 - m^2 a^2 e^2}{1 + m^2} = b^2.
100. PROP. VII.—To find the equation to the ellipse when referred to two diameters as axes, of which the one is parallel to a tangent at the extremity of the other.
Let CP be one diameter, and CD parallel to the tangent at P the extremity of the other.
Let the co-ordinates of P, referred to the axes as before, be x', y'; of Q, x, y, and let the co-ordinates of Q referred to CP and CD be x and y, or CV = x, QV = y; also let the angle PCA = \theta, DCO = \phi; then \tan \phi = \frac{b^2 x'}{a^2 y'}, and \tan \theta = \frac{y}{x};
\therefore \tan \theta \tan \phi = \frac{b^2}{a^2}; \text{ i. e., } a^2 \sin \theta \sin \phi = b^2 \cos \theta \cos \phi.
\text{And (Art. 41) } \begin{aligned} x_1 &= x \cos \theta - y \cos \phi, \\ y_1 &= x \sin \theta + y \sin \phi. \end{aligned}
Substituting these values in the equation a^2 y_1^2 + b^2 x_1^2 = a^2 b^2, there results
\begin{aligned} a^2(x \sin \theta + y \sin \phi)^2 + b^2(x \cos \theta - y \cos \phi)^2 &= a^2 b^2, \\ \text{or } a^2(x^2 \sin^2 \theta + y^2 \sin^2 \phi) + b^2(x^2 \cos^2 \theta + y^2 \cos^2 \phi) &= a^2 b^2, \\ \text{or } a^2 y^2 + b^2 x^2 &= a^2 b^2, \text{ where} \end{aligned}
a^2 = \frac{a^2 b^2}{a^2 \sin^2 \theta + b^2 \cos^2 \phi}, \quad b^2 = \frac{a^2 b^2}{a^2 \sin^2 \phi + b^2 \cos^2 \theta}.
101. COR. 1.—Since only the squares of x and y appear in the equation, the line CP bisects all chords parallel to CD, or (Art. 50) the diameters CP, CD are conjugate diameters, and CP is parallel to the tangent at D.
102. COR. 2.—By making successively x = 0 and y = 0, we obtain CP = a, CD = b. Hence the equation is exactly the same as when referred to the principal axes; and the results obtained in that case are easily adapted to the present.
\begin{aligned} 103. \text{ COR. 3.} &—\text{We have} \\ a^2 \sin^2 \theta : b^2 \cos^2 \phi &:: a^2 \tan^2 \phi + b^2 : a^2 + b^2 \cot^2 \theta, \\ &:: \frac{b^2 x^2}{a^2 y^2} + b^2 : a^2 + \frac{b^2 + a^2}{y^2}, \\ &:: b^2 : a^2, \end{aligned}
\begin{aligned} \therefore PM : CN &:: b : a, \\ \text{Similarly } DN : CM &:: b : a, \\ \therefore PM : CN &:: DN : CM. \end{aligned}
\begin{aligned} 104. \text{ COR. 4.} &—CP^2 + CD^2 = CM^2 + MP^2 + CN^2 + ND^2 \\ &= CM^2 + MP^2 + \frac{a^2}{b^2} MP^2 + \frac{b^2}{a^2} CM^2 \\ &= (a^2 + b^2) \left( \frac{CM^2}{a^2} + \frac{MP^2}{b^2} \right) \\ &= a^2 + b^2; \end{aligned}
or the sum of the squares of any two conjugate axes is the same as the sum of the squares of the principal axes.
\begin{aligned} 105. \text{ COR. 5.} &—CD^2 = \frac{a^2}{b^2} y^2 + \frac{b^2}{a^2} x^2, \\ &= a^2 \left( 1 - \frac{x^2}{a^2} \right) + \frac{b^2}{a^2} x^2 \\ &= a^2 - e^2 x^2 \\ &= FP \cdot SP \quad (\text{Art. 15}). \end{aligned}
106. PROP. VIII.—All parallelograms circumscribing the ellipse are equal.
If tangents be drawn at the extremities of conjugate diameters, they will form a parallelogram of which the

Analytical Geometry. area is 4 a b \sin (\theta + \phi)
= 4 a b \sin \theta \cos \phi + 4 a b \cos \theta \sin \phi
= 4 \text{ PM} \cdot \text{CN} + 4 \text{ CM} \cdot \text{DN}
= 4 \frac{a}{b} \text{ PM}^2 + 4 \frac{b}{a} \text{ CM}^2 (Art. 103)
= 4 a b \left( \frac{\text{PM}^2}{b^2} + \frac{\text{CM}^2}{a^2} \right) = 4 a b.

107. PROP. IX.—The ellipse is the curve generated by a point whose distance from the focus is to its distance from the directrix as e:1.

Let \text{EQ} be the directrix at a distance from the centre \text{CE} = \frac{a}{e}; then

\text{PQ} = \text{ME} = \text{CE} - \text{CM} = \frac{a}{e} - x = \frac{a - ex}{e} = \frac{\text{FP}}{e}

(Art. 15); \therefore \text{FP} : \text{PQ} :: e : 1.

Figure 26: A diagram of an ellipse with center C and focus M. A point P is on the ellipse. A vertical line segment MP is drawn from P to the major axis. A horizontal line segment PQ is drawn from P to the directrix EQ. The distance CE is labeled as a/e. The distance CM is labeled as x. The distance FP is labeled as a - ex. The distance PQ is labeled as (a - ex)/e.

5. The Hyperbola.

The equation to the hyperbola differs from that to the ellipse only in having -b^2 in place of b^2. With this limitation, the properties given above and their demonstrations are common to both curves, and it would be superfluous to repeat them. We shall, accordingly, confine ourselves to that property of the hyperbola which has no parallel in the ellipse—the asymptote and its consequences.

108. PROP. I.—To find the equation to the asymptote of the hyperbola.

We have already (Art. 30) shown that if the values of y be expressed in a descending series of powers of x, the equation to the asymptote may be obtained from it by omitting all negative powers.

Now in the hyperbola (Art. 17)—

\begin{aligned} y^2 &= \frac{b^2}{a^2} (x^2 - a^2) \\ &= \frac{b^2}{a^2} x^2 \left( 1 - \frac{a^2}{x^2} \right) \\ \therefore y &= \pm \frac{b}{a} x \left( 1 - \frac{1}{2} \frac{a^2}{x^2} + \dots \right) \end{aligned}

Hence the straight line whose equation is y = \pm \frac{b}{a} x is an asymptote to the curve.

If the curve be referred to conjugate diameters, the same reasoning will show that the equation to the asymptotes is

y = \pm \frac{b}{a} x.

It is evident that the asymptotes are the diagonals of a parallelogram of which the conjugate diameters are the lines joining the points of bisection of opposite sides.

109. PROP. II.—If any chord of the hyperbola be terminated by the asymptotes, the rectangle by its segments is equal to the square of the semi-axis parallel to that chord.

Let \text{RPQH} (fig. 27) be a chord terminated by the asymptotes; then \text{RP} \cdot \text{PH} = b^2.

Let the curve be referred to conjugate diameters, of which one is parallel to \text{RH}; its equation is

y^2 = \frac{b^2}{a^2} (x^2 - a^2);

and the equation to the asymptote

y^2 = \frac{b^2}{a^2} x^2.
\therefore y^2 - y^2 = \frac{b^2}{a^2} a^2 = b^2;
\text{i.e. } \text{MR}^2 - \text{MP}^2 = b^2.

Now \text{MP} = \text{MQ} being respectively \pm \frac{b}{a} \sqrt{x^2 - a^2}, and

\text{MR} = \text{MH} \text{ being respectively } \pm \frac{b}{a} x;

\therefore the above equation gives \text{RP} \cdot \text{PH} = b^2.

110. PROP. III.—To find the equation to the curve when referred to the asymptotes as axes.

Draw \text{NP} parallel to \text{CR}, and let \text{CN} = x', \text{NP} = y'.

Suppose \text{CM} in the direction of the transverse* axis = x, \text{MP} perpendicular to it = y, the angle \text{RCM} = \theta; then x = x' \cos \theta + y' \sin \theta, y = y' \sin \theta - x' \cos \theta; \therefore a^2 (y' - x')^2 \sin^2 \theta - b^2 (x' + y')^2 \cos^2 \theta = -a^2 b^2.

\text{Now } \tan \theta = \frac{b}{a};
\therefore \sin^2 \theta = \frac{b^2}{a^2 + b^2};
\cos^2 \theta = \frac{a^2}{a^2 + b^2};
\text{hence } \frac{a^2 b^2}{a^2 + b^2} \left\{ (y' - x')^2 - (x' + y')^2 \right\} = -a^2 b^2;
\text{or } x'y' = \frac{a^2 + b^2}{4}, \text{ the equation required.}

111. PROP. IV.—If any tangent be produced to meet the two asymptotes, the area of the triangle contained by the tangent and the two asymptotes is always the same.

Let \text{UPT} be the tangent; its equation (Art. 55);

xy' + yx' = \frac{a^2 + b^2}{2}.
\text{Now, when } y=0, x=\text{CT}; \quad \therefore \text{CT} = \frac{a^2 + b^2}{2y'};
\text{and when } x=0, y=\text{CU}; \quad \therefore \text{CU} = \frac{a^2 + b^2}{2x'}.
\text{Hence } \text{CT} \cdot \text{CU} = \frac{(a^2 + b^2)^2}{4x'y'} = a^2 + b^2;

and as the angle \text{TCU} is constant, the area \text{TCU} is always the same, whatever be the point \text{P}.

We cannot close this portion of our subject without acknowledging our obligations to Mr Salmon, whose masterly treatise can hardly be too highly recommended.

ANALYTICAL GEOMETRY OF THREE DIMENSIONS; OR SOLID CO-ORDINATE GEOMETRY.

1. As in plane co-ordinate geometry, the position of a point in a plane is denoted by its distances from two given lines, so in solid geometry the position of a point in space

* The terms transverse and conjugate are more appropriate than major and minor in the case of the hyperbolas.

is denoted by its distances from three given planes. The direction in which the distance from any one plane is measured is parallel to the line of intersection of the other two. The planes of reference are called the co-ordinate planes, and their lines of intersection the co-ordinate axes; the point in which the three intersect one another being the origin.

SECTION I.—PROPERTIES OF THE PLANE AND STRAIGHT LINE.

We shall at present confine ourselves to rectangular axes.

2. PROP. I.—To find the distance between two points in terms of their co-ordinates.

Let Ox, Oy, Oz be the axes of co-ordinates; P, Q the two points; x, y, z the co-ordinates of P; x', y', z' the co-ordinates of Q. Through P, Q draw planes parallel to the co-ordinate planes of xy, xz, yz; it is evident that they will form a parallelepipedon, of which PQ is the diagonal. Let QM be the edge of this parallelepipedon parallel to x, MN parallel to y, and NP to z; then it is evident that QM = x - x', MN = y - y', NP = z - z'; and QM being perpendicular to the plane PMN, the angle QMP is a right angle.

Fig. 28.
\therefore PQ^2 = QM^2 + MP^2 = QM^2 + MN^2 + NP^2 \\ = (x - x')^2 + (y - y')^2 + (z - z')^2.

3. COR. 1.—If \alpha, \beta, \gamma be the angles which PQ makes with the axes of x, y, z, we shall have

x - x' = QM = PQ \cos \alpha, \quad y - y' = PQ \cos \beta, \\ z - z' = PQ \cos \gamma;
\therefore PQ^2 = PQ^2 \cos^2 \alpha + PQ^2 \cos^2 \beta + PQ^2 \cos^2 \gamma,

and \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 1; consequently the angles which a straight line makes with the axes are not all three arbitrary, but where two are given, the third is determined by the above equation.

4. COR. 2.—If we take the three equations, x - x' = PQ \cos \alpha, y - y' = PQ \cos \beta, z - z' = PQ \cos \gamma, and multiply the first by x - x', the second by y - y', and the third by z - z', and add the results, we shall get (x - x') \cos \alpha + (y - y') \cos \beta + (z - z') \cos \gamma = PQ.

5. PROP. II.—To find the angle between two straight lines in terms of the angles which the lines make with the axes.

Draw through the origin two lines OP, OQ parallel to the given lines, and let OP make with the axes the angles \alpha, \beta, \gamma, and OQ the angles \alpha', \beta', \gamma'.

Take OP = 1, OQ = 1, and let the angle POQ be \theta; then x = OP \cos \alpha = \cos \alpha, y = \cos \beta, &c. Now PQ^2 = OP^2 + OQ^2 - 2 OP \cdot OQ \cos \theta, = 2 - 2 \cos \theta.

\text{But } PQ^2 = (x - x')^2 + (y - y')^2 + (z - z')^2 \\ = (\cos \alpha - \cos \alpha')^2 + (\cos \beta - \cos \beta')^2 \\ + (\cos \gamma - \cos \gamma')^2 \\ = \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma + \cos^2 \alpha' + \cos^2 \beta' + \cos^2 \gamma' \\ - (2 \cos \alpha \cos \alpha' + \cos \beta \cos \beta' + \cos \gamma \cos \gamma') \\ = 2 - 2(\cos \alpha \cos \alpha' + \cos \beta \cos \beta' + \cos \gamma \cos \gamma'); \\ \therefore \cos \theta = \cos \alpha \cos \alpha' + \cos \beta \cos \beta' + \cos \gamma \cos \gamma'.

6. PROP. III.—To find the equation to a plane.

Let ABC be the plane, P any point in it, of which the co-ordinates are x, y, z; OQ perpendicular to the plane = p, making with the axes of x, y, and z the angles \alpha, \beta, and \gamma.

Let also OP make with the axes the angles \alpha', \beta', \gamma'; then, as in Art. 3, we have x = OP \cos \alpha', y = OP \cos \beta', z = OP \cos \gamma'.

\text{Now } OQ = OP \cos \angle POQ \\ = OP (\cos \alpha \cos \alpha' + \cos \beta \cos \beta' + \cos \gamma \cos \gamma') \quad (\text{Art. 5}),
\text{or } p = x \cos \alpha + y \cos \beta + z \cos \gamma.

7. COR. 1.—If OA = a, OB = b, OC = c, we have

\cos \alpha = \frac{p}{a}, \quad \cos \beta = \frac{p}{b}, \quad \cos \gamma = \frac{p}{c};
\therefore x \cos \alpha + y \cos \beta + z \cos \gamma = \frac{xp}{a} + \frac{yp}{b} + \frac{zp}{c};

hence \frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1, is another form of the equation.

8. COR. 2.—Any simple equation in x, y, z of which the general form is Ax + By + Cz = D will represent a plane.

9. COR. 3.—If the equation be written in the form exhibited in the last corollary, we must have

\frac{\cos \alpha}{p} = \frac{A}{D}, \quad \frac{\cos \beta}{p} = \frac{B}{D}, \quad \frac{\cos \gamma}{p} = \frac{C}{D};
\therefore (\text{Art. 3}) \quad \frac{1}{p^2} = \frac{A^2 + B^2 + C^2}{D^2},
\text{or } p = \frac{D}{\sqrt{A^2 + B^2 + C^2}}.
\cos \alpha = \frac{A}{\sqrt{A^2 + B^2 + C^2}}, \quad \cos \beta = \frac{B}{\sqrt{A^2 + B^2 + C^2}},
\cos \gamma = \frac{C}{\sqrt{A^2 + B^2 + C^2}}.

10. COR. 4.—If z = 0 in Cor. 1, we get \frac{x}{a} + \frac{y}{b} = 1, which is obviously the equation to the line AB. This line is called the trace of the plane on the plane of xy. In like manner, AC, BC are the traces of the plane on the planes of xz and yz.

11. COR. 5.—If the plane be parallel to the axis of z or perpendicular to the plane of xy, the line OQ is in the plane of xy; \therefore \gamma = \frac{\pi}{2} and \cos \gamma = 0; hence the equation to the plane becomes x \cos \alpha + y \cos \beta = p, or the equation to the plane is the same as the equation to its trace on the plane of xy.

12. PROP. IV.—To find the equations to a straight line.

A straight line is the intersection of two planes, consequently the equations to those planes will be satisfied simultaneously for the line. These are therefore the equations to the line.

If the two equations be Ax + By + Cz = D and A'x + B'y + C'z = D', we may obtain by elimination

x = az + p, \quad y = bz + q

as the form of the equations required.

13. The equations are sometimes obtained in the following manner:—

Let planes pass through the line respectively perpendicular to the planes of xz and yz. Their equations will have

Analytical Geometry. the form (Art. 11) x=az+p, y=bz+q, which are the equations to the line.

14. COR. 1.—It is evident that if perpendiculars be drawn from every point in the given line to the plane of xz, they will intersect that plane in the line whose equation is x=az+p. This latter line is called the projection of the given line on the plane of xz. Consequently, the equations to a line are the equations to its projections on two of the co-ordinate planes.

15. PROP. V.—To express the angles which a straight line makes with the co-ordinate axes in terms of a and b.

Let PQ, fig. of Art. 2, be the line, x=az+p, y=bz+q its equations; then because the point Q, of which the co-ordinates are x', y', z', is a point in the line, we have

x-x' = a(z-z'), \quad y-y' = b(z-z'),
\text{and } \cos \alpha = \frac{x-x'}{PQ}, \quad \cos \beta = \frac{y-y'}{PQ}, \quad \cos \gamma = \frac{z-z'}{PQ};
\text{i.e. } \cos \alpha = \frac{x-x'}{\sqrt{(x-x')^2 + (y-y')^2 + (z-z')^2}} = \frac{a}{\sqrt{a^2 + b^2 + 1}};
\cos \beta = \frac{b}{\sqrt{a^2 + b^2 + 1}}, \quad \cos \gamma = \frac{1}{\sqrt{a^2 + b^2 + 1}}.
16. \text{ COR. 1.} \text{—} a = \frac{\cos \alpha}{\cos \gamma}, \quad b = \frac{\cos \beta}{\cos \gamma}.
17. \text{ COR. 2.} \text{—} \frac{x-x'}{a} = \frac{y-y'}{b} = z-z';
\text{or } \frac{x-x'}{\cos \alpha} = \frac{z-z'}{\cos \gamma} \quad \text{and} \quad \frac{y-y'}{\cos \beta} = \frac{z-z'}{\cos \gamma};

which are the equations to a straight line in terms of the angles which it makes with the co-ordinate axes.

18. COR. 3.—If x=a'z+p', y=b'z+q' be the equations to another straight line; then, if \theta be the angle between them, we shall have

\cos \theta = \cos \alpha \cos a' + \cos \beta \cos \beta' + \cos \gamma \cos \gamma' \quad (\text{Art. 5}) \\ = \frac{aa' + bb' + 1}{\sqrt{a^2 + b^2 + 1} \sqrt{a'^2 + b'^2 + 1}}.

19. COR. 4.—In order that the two straight lines may be at right angles to one another, we must have \cos \theta = 0, or aa' + bb' + 1 = 0.

20. PROP. VI.—To find the conditions that a straight line may be at right angles to a plane.

It is evident that the angles determined in Art. 9, which the perpendicular to the plane makes with the axes, must be equal to those determined in Art. 15, which the straight line makes with them; or

\frac{A}{\sqrt{A^2 + B^2 + C^2}} = \frac{a}{\sqrt{a^2 + b^2 + 1}}, \quad \frac{B}{\sqrt{A^2 + B^2 + C^2}} = \frac{b}{\sqrt{a^2 + b^2 + 1}}, \\ \frac{C}{\sqrt{A^2 + B^2 + C^2}} = \frac{1}{\sqrt{a^2 + b^2 + 1}};

\therefore A = aC, B = bC are the conditions required.

21. PROP. VII.—To find the conditions that a straight line may coincide with a plane.

Let x=az+p, y=bz+q be the equations to the line; Ax+By+Cz=D the equation to the plane; then, since they coincide, we must have A(az+p) + B(bz+q) + Cz = D, whatever be z; hence Aa+Bb+C=0 and Ap+Bq=D are the conditions required.

22. COR.—The condition that the straight line may be parallel to the plane is Aa+Bb+C=0; being the con-

dition that a line and plane parallel to these through the origin shall coincide.

23. PROP. VIII.—To find the length of the perpendicular from a given point on a given plane.

Let P be the point of which the co-ordinates are x', y', z'; PR perpendicular to the plane whose equation is Ax+By+Cz=D.

Draw PQ parallel to the axis of z, meeting the plane in Q; then PR = PQ \cos QPR

= PQ \frac{C}{\sqrt{A^2 + B^2 + C^2}} \quad (\text{Art. 9});
\text{But } PQ = z' - \frac{D - Ax' - By'}{C},
\therefore PR = \frac{Ax' + By' + Cz' - D}{\sqrt{A^2 + B^2 + C^2}}.
Figure 30: A 3D diagram showing a point P above a plane. A line PQ is drawn parallel to the z-axis, intersecting the plane at Q. A perpendicular PR is drawn from P to the plane. The plane is represented by a triangle with vertices labeled.
Fig. 30.

24. If from every point in the boundary of a given surface, straight lines be drawn parallel to a given line and meeting a fixed plane, they form the boundary of the projection of the surface on that plane. When the lines are drawn perpendicular to the plane, the projection is called an orthogonal projection. It is with this class alone that we are concerned here.

PROP. IX.—The projection of a plane area is to the area itself, as the cosine of the angle between the two planes is to unity.

Suppose the area divided into triangles, indefinitely small if necessary. Let ABC

be one of these triangles, DEF its projection; and let the line of intersection of the planes of ABC, DEF be GK. Through A, B, C draw planes at right angles to GK, and therefore passing through D, E, and F; each of the angles AGD, PHQ, CKF is equal to the angles between the planes.

Figure 31: A 3D diagram showing a plane area ABC and its projection DEF on a parallel plane. A line GK is the intersection of the two planes. Planes are drawn through A, B, C and D, E, F perpendicular to GK. Points P, Q, R are on these planes.
Fig. 31.

Now the triangles ABP, DEQ have BP, EQ as their bases, and GH as their common altitude;

\therefore DEQ : ABP :: EQ : BP \\ :: \cos PHQ : 1.

Similarly of the other triangles. Hence the truth of the proposition.

25. PROP. X.—The square of any plane area is equal to the sum of the squares of its projections on the three co-ordinate planes.

Let A_x, A_y, A_z represent the projections of A on the planes of yz, xz, and xy; \alpha, \beta, \gamma, the angles which the perpendicular on A makes with the axes of x, y, and z; then \alpha is the angle which the area makes with the plane of yz. \therefore A_x = A_y \cos \alpha. Similarly A_y = A \cos \beta, A_z = A \cos \gamma. Now \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 1; \therefore A_x^2 + A_y^2 + A_z^2 = A^2.

26. PROP. XI.—To find the equation to a plane in terms of the area and its projections on the co-ordinate planes.

As in the last proposition A = A_x \cos \alpha, &c.

\therefore \cos \alpha = \frac{A_x}{A}, \quad \cos \beta = \frac{A_y}{A}, \quad \cos \gamma = \frac{A_z}{A}.

Now (Art. 6) the equation to the plane is
x \cos \alpha + y \cos \beta + z \cos \gamma = p;
hence it becomes x A_x + y A_y + z A_z = p A.

28. PROP. XII.—The projection of a straight line on a plane is to the straight line, as the cosine of the angle between them is to unity.

Let AB be the straight line meeting the plane in E; CD the projection; then AC, BD, which are perpendicular to ED, are in the plane BED at right angles to the plane of projection; and AEC or its equal BAF is the angle between the straight line and the plane; hence

CD : AB :: \cos E : 1.
Figure 32: A geometric diagram showing a line segment AB in space. A plane BED is shown, with E being the intersection of AB and the plane. CD is the projection of AB onto the plane BED. AC and BD are perpendicular to the plane BED. The angle AEC is labeled as the angle between the line and the plane.
Fig. 32.

29. PROP. XIII.—The projection of a straight line on another straight line is to the straight line itself, as the cosine of their angle of inclination is to unity.

When two lines are not in the same plane, their angle of inclination is the angle which one of them makes with a straight line drawn through it parallel to the other.

Let AB be the line to be projected; CD the line on which it is to be projected. Draw AE parallel to CD; then BAE is the angle of inclination of the lines. Through B draw the plane BFE perpendicular to CD, and therefore to AE; and draw AC parallel to EF. Then EFC, BFC, AEB are right angles, \therefore AF is a parallelogram and AE = CF the projection of AB on CD. But
AE : AB :: \cos BAE : 1;
\therefore CF : AB :: \cos BAE : 1.

Figure 33: A geometric diagram showing a line segment AB in space. A line CD is shown on a plane. AE is drawn parallel to CD. BAE is the angle of inclination. A plane BFE is drawn perpendicular to CD. AC is drawn parallel to EF. The diagram illustrates the projection of AB onto CD.
Fig. 33.

30. PROP. XIV.—If any two points be connected both by a straight and by a broken line, the projection of the former on a given line is equal to the sum of the projections of every part of the latter.

The projection of PQ on the line AB is equal to the sum of the projections of PM, MN, NR, RQ. Through P, M, N, R, Q draw planes perpendicular to AB; the intercepted portions of AB are the projections of PM, MN, &c.; hence the proposition is evidently true provided none of the intercepted portions lap over each other or are negative, as would be the case with the projection of MN in the following figure. But the cosines employed will rectify this, provided we attend to the directions of the lines as indicated in the figure by the arrows. For the projection of MN will be negative, because the angle is greater than a right angle, whilst all the others will be positive, including that of RQ, for which the angle is negative, but its cosine positive.

Figure 34: A geometric diagram showing a line segment PQ in space. A line AB is shown. Projections of P, M, N, R, and Q onto AB are marked. Arrows indicate the directions of the lines and the projections.
Fig. 34.

31. By a similar process, and retaining the same restriction as to direction, we may show that if an area be connected with any number of areas, having common edges with the former area and with each other, the projection of the former on any plane is equal to the sum of the projections of all the others.

32. a.—The Sphere.

The characteristic property is that every point is equally distant from the centre.

Let a, b, c be the co-ordinates of the centre, and r the radius. The equation is evidently

(x-a)^2 + (y-b)^2 + (z-c)^2 = r^2.

33. b.—Oblique Cylinder on a Circular Base.

We shall give the simplest form of the equation, by supposing the circular base to be in the plane of xy with its centre at the origin, so that its equation is x^2 + y^2 = r^2. This circle is called the directrix. A straight line moves parallel to itself in such a way as always to pass through the circumference of this circle. This line is called the generatrix. Let x = az + p, y = bz + q be its equation. Then a, b, r are known constants. Now p, q are the values of x and y when z=0; they are therefore the co-ordinates of a point in the circumference of the directrix, or p^2 + q^2 = r^2, i. e. (x-az)^2 + (y-bz)^2 = r^2, which is the equation required.

34. CON.—A similar process will determine the equation to the cylinder whatever be the equation to the directrix.

35. c.—Oblique Cone on a Circular Base.

We shall suppose the circle to be the same as in Art. 33. The generatrix is now required to pass through a fixed point called the vertex of the cone. Let a, b, c be the co-ordinates of this point; x = Az + p, y = Bz + q, the equations to the generatrix: then we must have a = Ae + p, b = Be + q, from which equations we obtain

p = \frac{az - ex}{z - c}, \quad q = \frac{bz - ey}{z - c},

and, since p^2 + q^2 = r^2, the equation required is (az - ex)^2 + (bz - ey)^2 = r^2(z - c)^2.

36. d.—The Ellipsoid.

The directrices are two ellipses at right angles to each other, having a common axis. We shall suppose their planes to be those of xy and xz. The generatrix is a variable ellipse, such that its semi-axes are the ordinates of the directrices.

Figure 35: A geometric diagram showing an ellipsoid with vertices A, B, C. The directrices are shown as ellipses in the xy and xz planes. A generatrix is shown as a variable ellipse passing through a point P. The semi-axes of the generatrix are the ordinates of the directrices.
Fig. 35.

Let \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 (1) be the equation to AOB,

\frac{x^2}{a^2} + \frac{z^2}{c^2} = 1 (2) the equation to AOC,

the two directrices; so that OA = a, OB = b, OC = c. The equation to the generatrix RPQ will be

\frac{y^2}{MQ^2} + \frac{z^2}{MR^2} = 1 \dots \dots \dots (3)

But by equations (1) and (2) MQ^2 = b^2 \left(1 - \frac{x^2}{a^2}\right), MR^2 =

c^2 \left(1 - \frac{x^2}{a^2}\right). Hence (3) becomes

\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1.

37. CON.—If b=c, the ellipsoid becomes a spheroid, prolate or oblate according as b is less or greater than a.

38. e.—Paraboloid of Revolution.

The directrix is a parabola, which we shall suppose to be in the plane of xz, the axis of x being its axis, so that its equation is z^2 = 4ax. The generatrix is a variable circle in the plane of yz, such that its radius is always the ordinate of the parabola. The equation to the generatrix is y^2 + z^2 = \text{radius}^2, \therefore y^2 + z^2 = 4ax is the equation required.

39. f.—Hyperboloid of One Sheet.

This surface differs from the ellipsoid only in having the directrices two hyperbolas, with a common conjugate axis. Hence a^2 is negative, and the equation is therefore

\frac{y^2}{b^2} + \frac{z^2}{c^2} - \frac{x^2}{a^2} = 1.
Figure 38: A 3D diagram showing a hyperboloid of one sheet. It features a vertical axis with points P, Q, R, and a horizontal axis with points M, N, O. A hyperbola is shown in the xz-plane, and a circle is shown in the yz-plane. Projections are indicated by lines connecting points on the hyperbola to the circle and to the axes.
Fig. 38.
40. h.—Hyperboloid of Two Sheets.

This surface differs from the ellipsoid only in having the directrices hyperbolas with their transverse axis common. Hence b^2 and c^2 are negative, and the equation is therefore

\frac{x^2}{a^2} - \frac{y^2}{b^2} - \frac{z^2}{c^2} = 1.
Figure 39: A 3D diagram showing a hyperboloid of two sheets. It features a vertical axis with points P, Q, R and a horizontal axis with points M, N, O. A hyperbola is shown in the xz-plane, and a circle is shown in the yz-plane. Projections are indicated by lines connecting points on the hyperbola to the circle and to the axes.
Fig. 39.
41. h.—Elliptic Paraboloid.

The directrices are here two parabolas placed as the two ellipses were in the case of the ellipsoid. The generatrix is a variable ellipse as before.

In the figure of last Article, if we suppose AB, AC to be two parabolas whose equations are MQ^2 = 4ax, MR^2 = 4bx, the origin being at A, we shall have as the equation to the ellipse RPQ

\frac{y^2}{MQ^2} + \frac{z^2}{MR^2} = 1.
\frac{y^2}{4a} + \frac{z^2}{4b} = x \text{ is the equation required.}
42. i.—Hyperbolic Paraboloid.

The directrices are the same as in the last Article, but the generatrix is a variable hyperbola, whose semi-axes are the ordinates of the two parabolas. The equation to the hyperbola is therefore

\frac{y^2}{MQ^2} - \frac{z^2}{MR^2} = 1.

Hence the equation to the surface is

\frac{y^2}{4a} - \frac{z^2}{4b} = x.
Figure 40: A 3D diagram showing a hyperbolic paraboloid. It features a vertical axis with points P, Q, R and a horizontal axis with points M, N, O. A hyperbola is shown in the xz-plane, and a circle is shown in the yz-plane. Projections are indicated by lines connecting points on the hyperbola to the circle and to the axes.
Fig. 40.
SECTION III.—TRANSFORMATION OF CO-ORDINATES.

Hitherto we have supposed the system of co-ordinates to be rectangular. This is indeed the fundamental system; but for the solution of certain problems it is necessary to pass to an oblique system. The investigation of the requisite formulae will constitute the subject of the present section.

43. PROP. I.—To find the distance between two points in terms of their oblique co-ordinates.

Retaining the figure of Art. 2, and supposing the axes not to be at right angles, we have

\begin{aligned} PQ^2 &= QM^2 + MP^2 - 2 QM \cdot MP \cos QMP \\ &= QM^2 + MN^2 + NP^2 - 2 MN \cdot NP \cos MNP \\ &\quad - 2 QM \cdot MP \cos QMP. \end{aligned}

Now MP \cos QMP is the projection of MP on the line MQ, and is therefore (Art. 29) equal to the sum of the projections of MN and NP on the same line, i.e., to MN \cos NMQ + NP \cos AMQ. But if \alpha, \beta, \gamma be the angles yOz, xOz, xOy, it is evident that MNP, AMQ, and NMQ are their respective supplements; hence

\begin{aligned} PQ^2 &= QM^2 + MN^2 + NP^2 + 2 MN \cdot NP \cos \alpha + 2 QM \cdot MN \cos \gamma \\ &\quad + 2 QM \cdot MN \cos \gamma \\ &= (x-x')^2 + (y-y')^2 + (z-z')^2 + 2(y-y')(z-z') \cos \alpha \\ &\quad + 2(x-x')(z-z') \cos \beta + 2(x-x')(y-y') \cos \gamma. \end{aligned}
44. PROP. II.—To change the origin without altering the directions of the axes.

It is evident that this is effected by writing x' + a, y' + b, z' + c for x, y, z.

45. PROP. III.—To pass from a rectangular system to any other, the origin remaining unchanged.

Let OM = x, MN = y, NP = z; OM' = x', M'N' = y', N'P' = z'. If the line OP be projected on the line Ox, the projection is OM or x; and if the broken line OM', M'N', N'P' be projected on Ox, the projection is equal to

\begin{aligned} &x' \cos x'x + y' \cos y'x + z' \cos z'x, \\ &\therefore x = x' \cos x'x + y' \cos y'x + z' \cos z'x, \end{aligned}
Fig. 41.

care being taken, as in Art. 30, to take the angles x'x, &c. between the positive axis of x' and the positive axis of x.

\begin{aligned} \text{Similarly} \quad y &= x' \cos x'y + y' \cos y'y + z' \cos z'y, \\ z &= x' \cos x'z + y' \cos y'z + z' \cos z'z. \end{aligned}

Of the nine angles x'x, y'y, z'z employed above, six only are independent of one another; since by Art. 3 we have the three following relations between them, as conditions to be satisfied, viz.:

\begin{aligned} \cos^2 x'x + \cos^2 x'y + \cos^2 x'z &= 1, \\ \cos^2 y'y + \cos^2 y'z + \cos^2 y'x &= 1, \\ \cos^2 z'z + \cos^2 z'x + \cos^2 z'y &= 1. \end{aligned}

46. COR.—If the new axes are rectangular as well as the old, we have three other equations of condition amongst the angles, to be satisfied, viz.: -\cos x'y = 0, \cos x'z = 0, \cos y'z = 0, which give (Art. 5)

\begin{aligned} \cos x'x \cos y'y + \cos x'y \cos y'z + \cos x'z \cos y'z &= 0, \\ \cos x'x \cos z'z + \cos x'y \cos z'y + \cos x'z \cos z'x &= 0, \\ \cos y'y \cos z'z + \cos y'y \cos z'y + \cos y'z \cos z'x &= 0. \end{aligned}

These make up the six equations of condition.

47. PROP. IV.—To pass from one rectangular system to another in a form which shall involve only three angles.

To avoid the six equations of condition exhibited above, Euler devised the following beautiful method of transformation, which is of frequent use in the solution of Mechanical Problems.

Let the angle between the planes of xy and x'y' be called \theta; let also these two planes intersect in the line Ox_1, which makes with the axis of x the angle xOx_1 = \phi, and with the axis of x' the angle x'Ox_1 = \psi.

(1.) Transform the co-ordinates to x_1y_1z_1 in the plane of xy, the axis of z remaining unchanged; there results (PLANE GEOMETRY, Art. 40)

x = x_1 \cos \phi - y_1 \sin \phi, \\ y = x_1 \sin \phi + y_1 \cos \phi.

2.) Transform the co-ordinates to y_2z_2 in the plane yz, the axis of x_1 remaining unchanged; there results

y_1 = y_2 \cos \theta - z_2 \sin \theta, \\ z_1 = y_2 \sin \theta + z_2 \cos \theta.

(3.) Transform the co-ordinates to x'_1y'_1z'_1 in the plane x_1y_1z_1, the axis of z' remaining unchanged; there results

x_1 = x'_1 \cos \psi - y'_1 \sin \psi, \\ y_1 = x'_1 \sin \psi + y'_1 \cos \psi.

By substitution, we obtain

x = (x'_1 \cos \psi - y'_1 \sin \psi) \cos \phi - (x'_1 \sin \psi + y'_1 \cos \psi) \sin \phi \cos \theta \\ + z'_1 \sin \phi \sin \theta, \\ y = (x'_1 \cos \psi - y'_1 \sin \psi) \sin \phi + (x'_1 \sin \psi + y'_1 \cos \psi) \cos \phi \cos \theta \\ + z'_1 \cos \phi \sin \theta, \\ z = (x'_1 \sin \psi + y'_1 \cos \psi) \sin \theta + z'_1 \cos \theta, \text{ the requisite formulae.}

48. COR.—If \psi = 0,

x = x'_1 \cos \phi - (y'_1 \cos \theta - z'_1 \sin \theta) \sin \phi, \\ y = x'_1 \sin \phi + (y'_1 \cos \theta - z'_1 \sin \theta) \cos \phi, \\ z = y'_1 \sin \theta + z'_1 \cos \theta,

formulae which are of frequent use.

49. PROP. V.—To transform the co-ordinates from rectangular to polar.

Let OP (figure of Art. 45) = r, POz = \theta, NOx = \phi; then x = ON \cos \phi = r \sin \theta \cos \phi, y = r \sin \theta \sin \phi, and z = r \cos \theta are the requisite formulae.

SECTION IV.—TANGENT PLANES AND NORMALS TO SURFACES.

50. PROP. 1.—To find the equation to the tangent plane to a surface.

If such a plane exists, it must have the property that if a section of it and of the surface be made by a plane parallel to any of the co-ordinate planes, the section of the plane will be a tangent line to the section of the surface.

Let x, y, z be the co-ordinates of the point of contact, x', y', z' those of any point in the tangent plane; and let the equation to that plane be

z' - z = p(x' - x) + q(y' - y).

Put y' = y in the plane and in the surface; then, since the resulting line is a tangent to the resulting curve, we have

z' - z = \frac{dz}{dx}(x' - x), \quad y \text{ being constant;}
\therefore p = \frac{dz}{dx} \text{ the partial differential co-efficient.}

Similarly q = \frac{dz}{dy}.

51. COR.—If the equation to the surface be written under the form u = 0; and \frac{du}{dx}, \frac{du}{dy}, \frac{du}{dz} represent the partial differential co-efficients of u with respect to x, y, and z respectively; since the total differential co-efficient of u with

Figure 49: A 3D coordinate system showing a point P and its projections onto the xy-plane (Ox1y1z1) and the yz-plane (y2z2). The angle between the planes is theta, and the angle between the axes is phi and psi.
Fig. 49.

respect to x, when y is constant, must = 0, we shall have

\frac{du}{dx} + \frac{du}{dz} \frac{dz}{dx} = 0. \quad \text{Similarly } \frac{du}{dy} + \frac{du}{dz} \frac{dz}{dy} = 0.
\text{Hence } \frac{dz}{dx} = -\frac{du}{du'} \quad \frac{dz}{dy} = -\frac{du}{du'}

and the equation to the tangent plane becomes

(x' - x) \frac{du}{dx} + (y' - y) \frac{du}{dy} + (z' - z) \frac{du}{dz} = 0.

52. PROP. II.—To find the equation to the normal to a surface.

Retaining the notation of Art. 51; since the normal is perpendicular to the surface, and therefore to the tangent plane; if its equations are x' - x = a(z' - z), y' - y = b(z' - z), we must have (Art. 20)

\frac{du}{dx} - a \frac{du}{dz} = 0, \quad \frac{du}{dy} - b \frac{du}{dz} = 0;

whence the equations to the normal are,

(x' - x) \frac{du}{dz} = (z' - z) \frac{du}{dx}, \quad (y' - y) \frac{du}{dz} = (z' - z) \frac{du}{dy}.

53. COR.—The equations may also be written

x' - x + \frac{dz}{dx}(z' - z) = 0, \quad y' - y + \frac{dz}{dy}(z' - z) = 0.

54. EXAMPLE.—To find the equation to the tangent plane to the ellipsoid.

\text{We have } \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1;
\therefore \frac{dz}{dx} = -\frac{c^2 x}{a^2 z}, \quad \frac{dz}{dy} = -\frac{c^2 y}{a^2 z}

and the equation to the tangent plane becomes

z' - z + \frac{c^2 x}{a^2 z}(x' - x) + \frac{c^2 y}{a^2 z}(y' - y) = 0;
\text{or } \frac{zx'}{c^2} + \frac{zy'}{b^2} + \frac{xz'}{a^2} = \frac{z^2}{c^2} + \frac{y^2}{b^2} + \frac{x^2}{a^2} = 1.

55. If p be the perpendicular from the centre on the tangent; we have (Art. 23)

p = \frac{1}{\sqrt{\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2}}}.

56. PROP. III.—To find the locus of the intersection of the tangent plane of the ellipsoid with the perpendicular on it from the centre.

The equation to the tangent plane is

\frac{zx'}{c^2} + \frac{zy'}{b^2} + \frac{xz'}{a^2} = 1 \dots \dots \dots (1)

Consequently the equations to the perpendicular on it from the centre are (Art. 20)

x' = \frac{c^2 x}{a^2 z}, \quad y' = \frac{c^2 y}{b^2 z}, \quad \dots \dots \dots (2)

also

\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 \dots \dots \dots (3)
\text{From equations (2), } \frac{x}{a^2} = \frac{z}{c^2} x' \text{ and } \frac{y}{b^2} = \frac{z}{c^2} y';
\therefore \frac{xx'}{a^2} + \frac{yy'}{b^2} + \frac{zz'}{c^2} = \frac{z}{c^2}(x'^2 + y'^2 + z'^2),

Analytical Geometry. which, by equation (1), gives

z = \frac{a^2 z'}{x'^2 + y'^2 + z'^2} \quad \text{Similarly } y = \frac{b^2 y'}{x'^2 + y'^2 + z'^2};
x = \frac{a^2 x'}{x'^2 + y'^2 + z'^2}; \text{ and these values being substituted in equation (3), there results } a^2 x'^2 + b^2 y'^2 + c^2 z'^2 = (x'^2 + y'^2 + z'^2)^3, \text{ an equation which occurs in the undulatory theory of light.}
SECTION V.—ON THE CURVATURE OF SURFACES.

57. If through the normal to a surface different planes be drawn, their intersections with the surface will be plane curves, which will generally have different degrees of curvature depending on the direction of the tangent line; and, further, if other sections than those through the normal are drawn, they will determine curves which have different degrees of curvature for the same direction of the tangent line. We proceed to determine the radius of curvature of any such section.

58. PROP. I.—The sum of the reciprocals of the radii of curvature of any two normal sections at right angles to each other is constant.

Let the normal be taken as the axis of z, and consequently the tangent plane as the plane of xy.

Let also the angle which a section makes with the plane of xz be \theta.

It is evident that \frac{dz}{dx} = 0, \frac{dz}{dy} = 0. Put r for \frac{d^2 z}{dx^2}, s for

\frac{d^2 z}{dx dy}, t for \frac{d^2 z}{dy^2}; and let OM = k, MN = K; then if R be the radius of curvature of this section,

R = \frac{1}{2} \text{ limit of } \frac{ON^2}{PN} = \frac{1}{2} \text{ limit}

of \frac{k^2 + K^2}{\frac{r k^2}{2} + s k K + t \frac{K^2}{2} + \dots}

= \frac{1 + \tan^2 \theta}{r + 2s \tan \theta + t \tan^2 \theta}
\text{and } \frac{1}{R} = r \cos^2 \theta + 2s \sin \theta \cos \theta + t \sin^2 \theta.
\text{Let } \frac{1}{R} \text{ be the radius of curvature of the section at right angles to this, or for which the angle is } 90^\circ + \theta; \text{ then}
\frac{1}{R} = r \sin^2 \theta - 2s \sin \theta \cos \theta + t \cos^2 \theta;
\therefore \frac{1}{R} + \frac{1}{R} = r + t, \text{ which is independent of } \theta.

59. PROP. II.—To determine the sections of greatest and least curvature.

Retaining the notation of the last article, we have

\frac{1}{R} = r \cos^2 \theta + 2s \sin \theta \cos \theta + t \sin^2 \theta,

which will be a maximum or a minimum, when

-r \sin \theta \cos \theta + s (\cos^2 \theta - \sin^2 \theta) + t \sin \theta \cos \theta = 0,

or \tan 2\theta = \frac{2s}{r-t}; an equation which gives two values of \theta,

viz., \theta = \alpha, \theta = 90^\circ + \alpha, or the maximum and minimum sections are at right angles to each other. These are called the principal sections.

60. PROP. III.—The curvature of any normal section (measured by the reciprocal of the radius of curvature) is equal to the sum of the products of the curvatures of the two principal sections by the cosines of the angles which they respectively make with it.

Let one of the principal sections be the plane of xz, or let the two values of \theta be \theta = 0, \theta = 90^\circ. Let also \rho, \rho' be the two principal radii of curvature;

\text{then when } \theta = 0, \text{ we have } \frac{1}{\rho} = r,
\text{and when } \theta = 90^\circ, \frac{1}{\rho'} = t.

Also, since \tan 2\theta = 0, we have s = 0,

\therefore \frac{1}{R} = \frac{1}{\rho} \cos^2 \theta + \frac{1}{\rho'} \sin^2 \theta.

61. PROP. IV.—If through a given tangent line at any point, both a normal and an oblique section be made, the radius of curvature of the oblique section is equal to the projection on its plane of the radius of curvature of the normal section.

Let the axis of x be the given tangent, the plane of xz the normal section, that of xz' the oblique section.

Figure 42: A geometric diagram showing a point O as the origin. A vertical line represents the z-axis. A plane xz is shown, and a point P is on it. A normal section is drawn through O. An oblique section xz' is also shown, passing through O. Points M, N, P, P', and O are marked. The diagram illustrates the relationship between the normal and oblique sections.
Fig. 42.

Let OM = k, MP = z, MN = k', NP' = z', \angle zOz' = \theta, R the radius of curvature in the normal section xz, R' in the oblique section xz'.

\text{Then } R : R' :: \text{ limit of } \frac{OM^2}{MP^2} : \frac{OM^2}{MP'^2}
:: \text{ limit of } MP^2 : MP'^2
:: \text{ limit of } \frac{z^2}{\cos^2 \theta} : z^2
:: \text{ limit of } (rh^2 + 2shk' + tk'^2) : rh^2 \cos^2 \theta
:: 1 : \cos^2 \theta, \text{ because the limit of } \frac{k'}{k} = 0;

therefore R' = R \cos^2 \theta.

This is called Meunier's Theorem, and it establishes the fact, that if the diameter of a circle in the plane of yz be that of the circle of curvature of the normal section, the chord of the same circle in the direction of the oblique section will be the diameter of the circle of curvature of that section; and consequently if the diameter of a sphere be the diameter of curvature of any normal section, the chord of the same sphere made by an oblique section through the same tangent line will be the diameter of the circle of curvature of that section; or the sections of the sphere by planes through the same tangent line will all be circles of curvature of the corresponding sections of the surface; and conversely.

62. PROP. V.—To find the conditions that a section of a surface may have a contact of the second order with a circle.

We shall suppose the touching circle to be determined by the section of a sphere, the cutting plane which is common to it and the given surface being supposed to pass through their ordinate z, so as to have for its equation y' - y = m(x' - x); or if x + h, y + k are the co-ordinates of a point in the section of either surface near their point of contact, the increments are connected by the equation h = mh.

Let f(x, y, z) = 0 be the equation to the given surface; (X - \alpha)^2 + (Y - \beta)^2 + (Z - \gamma)^2 = R^2 the equation to the sphere of which the section has a contact of the second order with

the given surface at the point whose co-ordinates are x, y, z. Let z_1, Z_1 be the ordinates of points in the common section of the two surfaces near their point of contact; then at the point in the curve of which the co-ordinates are x+h, y+k, we have

z_1 = z + \frac{dz}{dx}h + \frac{dz}{dy}k + \frac{1}{2} \left( \frac{d^2z}{dx^2}h^2 + 2\frac{d^2z}{dx dy}hk + \frac{d^2z}{dy^2}k^2 \right) + \dots = z + \frac{dz}{dx}h + \frac{dz}{dy}k + \frac{h^2}{2} \left( \frac{d^2z}{dx^2} + 2m \frac{d^2z}{dx dy} + m^2 \frac{d^2z}{dy^2} \right) + \dots

and at the corresponding point in the circle,

Z_1 = Z + \frac{dZ}{dx}h + \frac{dZ}{dy}k + \frac{h^2}{2} \left( \frac{d^2Z}{dx^2} + 2m \frac{d^2Z}{dx dy} + m^2 \frac{d^2Z}{dy^2} \right) + \dots

But the requirement for a contact of the second order is, that to the extent of h^2 these two expressions shall be coincident.

The conditions to be fulfilled are, therefore,

\frac{dZ}{dx} = \frac{dz}{dx} \dots \dots \dots (1)
\frac{dZ}{dy} = \frac{dz}{dy} \dots \dots \dots (2)
\frac{d^2Z}{dx^2} - \frac{d^2z}{dx^2} + 2m \left( \frac{d^2Z}{dx dy} - \frac{d^2z}{dx dy} \right) + m^2 \left( \frac{d^2Z}{dy^2} - \frac{d^2z}{dy^2} \right) = 0 \dots \dots (3)

63. PROP. VI.—To find the radius of curvature and the co-ordinates of the centre of a normal section.

By differentiation, we obtain from the equation to the sphere of which the section of the normal plane is the circle of curvature

(X - \alpha)^2 + (Y - \beta)^2 + (Z - \gamma)^2 = R^2 \dots \dots \dots (1)
X - \alpha + (Z - \gamma) \frac{dZ}{dX} = 0 \dots \dots \dots (2)
Y - \beta + (Z - \gamma) \frac{dZ}{dY} = 0 \dots \dots \dots (3)
1 + \left( \frac{dZ}{dX} \right)^2 + (Z - \gamma) \frac{d^2Z}{dX^2} = 0 \dots \dots \dots (4)
\frac{dZ}{dX} \frac{dZ}{dY} + (Z - \gamma) \frac{d^2Z}{dX dY} = 0 \dots \dots \dots (5)
1 + \left( \frac{dZ}{dY} \right)^2 + (Z - \gamma) \frac{d^2Z}{dY^2} = 0 \dots \dots \dots (6)

Now the conclusion arrived at in Art. 61 enables us to apply the conditions of the last Article; for if the section of the sphere by one plane is a section of curvature, every

section is so. Hence if we write \frac{dz}{dx} = p, \frac{dz}{dy} = q, \frac{d^2z}{dx^2} = r,

\frac{d^2z}{dx dy} = s, \frac{d^2z}{dy^2} = t, we shall have, by equations (1) and (2)

of the last Article compared with (4), (5), and (6) of the present,

\frac{d^2Z}{dX^2} = -\frac{1+p^2}{Z-\gamma} \quad \frac{d^2Z}{dX dY} = -\frac{pq}{Z-\gamma} \quad \frac{d^2Z}{dY^2} = -\frac{1+q^2}{Z-\gamma}

and consequently equation (3) of the last Article gives

\left( \frac{1+p^2}{Z-\gamma} + r \right) + 2m \left( \frac{pq}{Z-\gamma} + s \right) + m^2 \left( \frac{1+q^2}{Z-\gamma} + t \right) = 0.
\text{Whence } Z - \gamma = -\frac{1+p^2 + 2mpq + m^2(1+q^2)}{r + 2ms + m^2t} \dots \dots (7)

Also by equations (2) and (3) we have

(X - \alpha)^2 = p^2(Z - \gamma)^2 \dots \dots \dots (8)
(Y - \beta)^2 = q^2(Z - \gamma)^2 \dots \dots \dots (9)

and hence by equation (1)

R^2 = (1 + p^2 + q^2)(Z - \gamma)^2 R = \sqrt{1 + p^2 + q^2} \frac{1 + p^2 + 2mpq + m^2(1 + q^2)}{r + 2ms + m^2t} \dots \dots (10)

Equations (7), (8), and (9) determine the co-ordinates of the centre; and equation (10) gives the value of the radius of curvature of the section.

SECTION VI.—THE GENERATION OF SURFACES BY THE MOTION OF LINES.

We propose in the present section to determine the ordinary and differential equations to cylindrical, conical, and conoidal surfaces, and to surfaces of revolution.

Cylindrical Surfaces.

64. To determine the ordinary equation, we adopt the definition, that cylindrical surfaces are generated by the motion of a straight line which always moves parallel to itself.

Let x = az + p, y = bz + q be the equations to the generating line, where a and b are the same for all the lines; and let x = F(z), y = \phi(z) be the equations to the directing curve: then at the points where the straight line meets the curve we have

x' = az' + p, y' = bz' + q, x' = F(z'), y' = \phi(z'); from which equations we may eliminate x, y, and z, and obtain a relation between p and q and the constants a and

b. Let this relation be p = f(q); i.e.

x - az = f(y - bz),

the equation required.

65. To obtain the differential equation, we observe that a tangent plane always touches the curve along one of the generating lines. Hence the line whose equation is x = az + p, y = bz + q is parallel to the plane whose equation is (Art. 50)

z' - z = \frac{dz'}{dx}(x' - x) + \frac{dz'}{dy}(y' - y).

The condition is (Art. 22) a \frac{dz'}{dx} + b \frac{dz'}{dy} = 1, which is the differential equation required.

Conical Surfaces.

66. A conical surface is generated by a straight line which passes through a given point, and always meets a given curve.

Let a, b, c be the co-ordinates of the given point; x = F(z), y = \phi(z), the equations to the given curve, the directrix; the equations to the generatrix are x - a = m(z - c), y - b = n(z - c); also at the point where the line meets the directrix we shall have x' - a = m(z' - c), y' - b = n(z' - c), y' = F(z'), y' = \phi(z'), from which equations x', y', z' may be eliminated, and there will remain

m = f(n), \text{ or } \frac{x - a}{z - c} = f\left(\frac{y - b}{z - c}\right),

the equation required.

67. To find the differential equation, it is only necessary to observe, that the tangent plane passes through the given

point; hence z - c = \frac{dz}{dx}(x - a) + \frac{dz}{dy}(y - b) is the differential equation required.